So I am trying to run sample code from the YouTube API. I am trying to run the Search sample code for Java. However, on line 70 and 71 where it says
InputStream in = Search.class.getResourceAsStream("/" + PROPERTIES_FILENAME);
properties.load(in);
I get an exceptions saying
Exception in thread "main" java.lang.NullPointerException: inStream parameter is null
at java.base/java.util.Objects.requireNonNull(Objects.java:246)
at java.base/java.util.Properties.load(Properties.java:403)
at com.google.api.services.samples.youtube.cmdline.data.Search.main(Search.java:71)
I have not modified the code and don't understand why this exception is occurring. It is acting as if the file does not exist when it is in the place that it was when I downloaded the .zip file.
Not certain as to why this was the case but there was an src folder, which contained a main folder that held a resources folder, which apparently was what .getResourcesStream was reading from rather than the other resources folder. So I updated this new folder and the code worked.
I solved this problem changing the original code provided by the API, and passing a single key inside the properties. Follow the code:
private static final String API_KEY = "XXX";
Properties properties = new Properties();
properties.setProperty(API_KEY, API_KEY);
// System.out.println(properties.getProperty(API_KEY));
Related
I want to copy and overwrite the existing file but cannot do it without getting the error nameAlreadyExists .
As a workaround I seem to have to download it into a stream and then reupload it.
The code is as per the API
await graphClient.Sites.Root.Drives[documentLibraryId].Items[fileId]
.Copy(newFileName, parentReference)
.Request()
.PostAsync();
As a workaround I may have to download the file into a strea and then upload it like as per the following which seems to work
await RetryWithExponentialBackoff.RunAsync(async () =>
{
uploadSession = await graphClient.Drives[driveId]
.Root
.ItemWithPath(filePath)
.CreateUploadSession()
.Request()
.PostAsync();
});
Usually you just need to set the microsoft.graph.conflictBehavior to replace. This works fine with functions such as moving. However, the Api ignores the specified conflict behavior with the copy function. More information on the bug here: link to github issue. It does not seem to be a priority for Microsoft, since the bug was reported over a year ago and nothing happened since. So you will most likely need a workaround.
Another idea for a workaround:
Copy the DriveItem to the target document library or folder, but use for example a combination of the current date and the drive item id instead of the desired file name newFileName to make sure, that you not get a conflict with any existing file.
Change the copied DriveItem's name to the desired file name newFileName, e. g.:
PATCH https://graph.microsoft.com/v1.0/sites/siteId/drives/driveId/items/itemId
{
"name": "newFileName",
"#microsoft.graph.conflictBehavior":"replace"
}
In my tests, this replaced the existing file with the name newFileName with the copied file.
With this workaround, you do not need to download and reupload the file. Thus, the performance should be better. However, the user may wonder about weird file names.
To read a properties file in JSF2.0 with Glassfishv3 webserver, which is located at root directory of my web application, I am using below code-
ServletContext ctx = (ServletContext) FacesContext
.getCurrentInstance().getExternalContext().getContext();
String deploymentDirectoryPath = ctx.getRealPath("/");
Properties prop = new Properties();
prop.load(new FileInputStream(deploymentDirectoryPath
+ File.separator + "portal-config.properties"));
Below is the screenshot of web portal-
While running the portal I am getting FileNotFound Error, since the file is not present in glassfish domain.
Is there any way to read properties file which can work in both the situations, at development stage and in war file also?
You should never use java.io.File to refer web resources. It knows nothing about the context it is sitting in. You should also never use ServletContext#getRealPath() as it may return null when the server is configured to expand WAR file in memory instead of on disk, which is beyond your control in 3rd party hosts.
Just use ExternalContext#getResourceAsStream() to get the web resource directly in flavor of an InputStream. It takes a path relative to the webcontent root.
ExternalContext ec = FacesContext.getCurrentInstance().getExternalContext();
properties.load(ec.getResourceAsStream("/portal-config.properties"));
See also:
getResourceAsStream() vs FileInputStream
What does servletcontext.getRealPath("/") mean and when should I use it
Where to place and how to read configuration resource files in servlet based application?
Update it does not seem to be a web resource at all. You should move the file into the "WebContent" folder as shown in the screenshot. Or, better, the /WEB-INF folder so that nobody can access it by URL.
properties.load(ec.getResourceAsStream("/WEB-INF/portal-config.properties"));
An alternative would be to put it in the classpath, the "Java source" folder as shown in the screenshot. You don't need to put it in a package, that's optional. Assuming that you didn't put it in a package, then do so:
ClassLoader cl = Thread.currentThread().getContextClassLoader();
properties.load(cl.getResourceAsStream("portal-config.properties"));
(note that the path may not start with a slash!)
I am new to Struts and working on File Upload using Struts.
Client:
It is Java Program which hits my Strut app by using apache HttpClient API and provides me
File.
Client as per need sometime gives me .wav file and sometime .zip file and sometime both.
Server:
Struts app which got the request from client app and upload the file.
Here, problem comes as I upload the file, it get uploaded using ".tmp" extension, which I want to get uploaded with the same extension what client has passed.
Or there is any other way by which we can check what is the extension of the file client has sent....?
I am stuck in this problem and not able to go ahead.
Please Find the code attached and tell me what modification I have to do:
Server Code:
MultiPartRequestWrapper multiWrapper=null;
File baseFile=null;
System.out.println("inside do post");
multiWrapper = ((MultiPartRequestWrapper)request);
Enumeration e = multiWrapper.getFileParameterNames();
while (e.hasMoreElements()) {
// get the value of this input tag
String inputValue = (String) e.nextElement();
// Get a File object for the uploaded File
File[] file = multiWrapper.getFiles(inputValue);
// If it's null the upload failed
if (file != null) {
FileInputStream fis=new FileInputStream(file[0]);
System.out.println(file[0].getAbsolutePath());
System.out.println(fis);
int ch;
while((ch=fis.read())!=-1){
System.out.print((char)ch);
}
}
}
System.out.println("III :"+multiWrapper.getParameter("method"));
Client code:
HttpClient client = new HttpClient();
MultipartPostMethod mPost = new MultipartPostMethod(url);
File zipFile = new File("D:\\a.zip");
File wavFile = new File("D:\\b.wav");
mPost.addParameter("recipientFile", zipFile);
mPost.addParameter("promptFile", wavFile);
mPost.addParameter("method", "addCampaign");
statusCode1 = client.executeMethod(mPost);
actually Client is written long back and cant be modified and I want to identify something at server side only to find the extension.
Please help, Thanks.
Struts2 File Uploader interceptor when uploading file pass the content type information to the Action class and one can easily find the file type by comparing contentType with MIME type.
If you want to can create a map with key as content type and file type as its value like
map.Add("image/bmp",".bmp", )
map.Add("image/gif",".gif", )
map.Add("image/jpeg",".jpeg", )
and can easily fetch the type based on the extension provides.Hope this will help you.
I have an .il file which I can compile without any problems. I can strong name it and so without any issues. But I am not able to set the file version via the attribute as I would expect it. How can I set the FileVersion for an assembly when using ilasm?
If I do a round trip I get always a .res file which does contain only binary data which is not readable. What is inside this res file and can I edit it?
The code does not work
.assembly myAssembly
{
.custom instance void [mscorlib]System.Reflection.AssemblyFileVersionAttribute::.ctor(string) = { string('1.2.3.4') }
The issue can be solved by using the .res file. It is not sufficient to do a round trip with ildasm and ilasm. The IL file does not reference the .res file. I had to add it to the ilasm call manually. The data in the res file seemed to contain the infos which are written into the PE header which is ok for me.
The final command line needed was
ilasm test.il /dll /res:test.res
I still do not know what exactly is inside the res file but I can exhange it with the meta data information of any other assemlby that I create manually and then decompile it to replace the metadata of the original assembly as I need.
It seems not many people are doing such stuff.
This one very simple thing I can't find the right technique. What I want is to open a .dotx template, make some changes and save as the same name but .docx extension. I can save a WordprocessingDocument but only to the place it's loaded from. I've tried manually constructing a new document using the WordprocessingDocument with changes made but nothing's worked so far, I tried MainDocumentPart.Document.WriteTo(XmlWriter.Create(targetPath)); and just got an empty file.
What's the right way here? Is a .dotx file special at all or just another document as far as the SDK is concerned - should i simply copy the template to the destination and then open that and make changes, and save? I did have some concerns if my app is called from two clients at once, if it can open the same .dotx file twice... in this case creating a copy would be sensible anyway... but for my own curiosity I still want to know how to do "Save As".
I would suggest just using File.IO to copy the dotx file to a docx file and make your changes there, if that works for your situation. There's also a ChangeDocumentType function you'll have to call to prevent an error in the new docx file.
File.Copy(#"\path\to\template.dotx", #"\path\to\template.docx");
using(WordprocessingDocument newdoc = WordprocessingDocument.Open(#"\path\to\template.docx", true))
{
newdoc.ChangeDocumentType(WordprocessingDocumentType.Document);
//manipulate document....
}
While M_R_H's answer is correct, there is a faster, less IO-intensive method:
Read the template or document into a MemoryStream.
Within a using statement:
open the template or document on the MemoryStream.
If you opened a template (.dotx) and you want to store it as a document (.docx), you must change the document type to WordprocessingDocumentType.Document. Otherwise, Word will complain when you try to open the document.
Manipulate your document.
Write the contents of the MemoryStream to a file.
For the first step, we can use the following method, which reads a file into a MemoryStream:
public static MemoryStream ReadAllBytesToMemoryStream(string path)
{
byte[] buffer = File.ReadAllBytes(path);
var destStream = new MemoryStream(buffer.Length);
destStream.Write(buffer, 0, buffer.Length);
destStream.Seek(0, SeekOrigin.Begin);
return destStream;
}
Then, we can use that in the following way (replicating as much of M_R_H's code as possible):
// Step #1 (note the using declaration)
using MemoryStream stream = ReadAllBytesToMemoryStream(#"\path\to\template.dotx");
// Step #2
using (WordprocessingDocument newdoc = WordprocessingDocument.Open(stream, true)
{
// You must do the following to turn a template into a document.
newdoc.ChangeDocumentType(WordprocessingDocumentType.Document);
// Manipulate document (completely in memory now) ...
}
// Step #3
File.WriteAllBytes(#"\path\to\template.docx", stream.GetBuffer());
See this post for a comparison of methods for cloning (or duplicating) Word documents or templates.