Closes SFSafariViewController on a certain url - ios

Question

I am trying to close SFSafariViewController when I reach a certain page.
But I am unable to do it until the "Done" button is pressed explicitly
by the user.
What I want is to get the URL as soon as it reached a certain page and then dismiss the view controller.
Then I can pick the rest using this
func safariViewControllerDidFinish(_ controller: SFSafariViewController){
// do work here
}
Note: This question has been asked before but I was unable to find any
satisfactory answers

Answer 1

If you register a URI scheme for your app, you could have have a link on a page which takes you back to your app. At that point you'll be in
func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {
of your AppDelegate and you can do whatever you wish.
“Because since Safari View Controller has access to a user’s
credentials, synced across all of their devices with iCloud Keychain,
logging in is going to be a breeze.[…] It takes two steps. The first
is where you would’ve used your own in-app browser, just present an
instance of SFSafariViewController.
And once the user is finished logging in and the third-party web
service redirects back to your app with the custom URL scheme that you
fed it, you can accept that in your AppDelegate‘s handleOpenURL
method.
From there you can inspect the response and dismiss the instance of
SFSafariViewController because you know that the authentication is
done.
That’s it. Two steps.”
Source: http://asciiwwdc.com/2015/sessions/504#t=1558.026
Please note the handleOpenURL method is deprecated in favor of application:openURL:options:.

Answer 2

Maybe It's late But I think It will help anyone search for the same question
Listening to the SFSafariViewControllerDelegate delegate you can use this method inside
func safariViewController(_ controller: SFSafariViewController, initialLoadDidRedirectTo URL: URL) {}
inside it you can make if condition on your certain page you need to take action for ... as example if I want to close it when reaching certain page I'will fo this
func safariViewController(_ controller: SFSafariViewController, initialLoadDidRedirectTo URL: URL) {
if URL.absoluteString == "WHATEVER YOUR LINK IS"{
controller.dismiss(animated: true, completion: nil)
}
}

Answer 3

You cannot do that with a SFSafariViewController. Use a WKWebView instead and implement the WKNavigationDelegate method like optional func webView(_ webView: WKWebView,
didFinish navigation: WKNavigation!) and then read the current URL. Define your action based on that.
You can use this to close the view controller that houses your web view. You will unfortunately have to build your own navigation buttons (the ones the SFSafariViewController has), if you want to allow the user access to those. You don't have to provide them.