Web Content Management how to find all the descendants of a content - wcm

I want to display all the descendant contents within a site area in IBM WCM.
But right now, I could only find API to find a certain item, but not all the descendants of that content.
The API for this is findAllByPath API:
DocumentIdIterator findAllByPath(java.lang.String namePath,
DocumentType documentType,
int workflowStatusFilter,
DocumentLibrary[] documentLibraries)
Thank you

not sure if you solved this but you can use the query service to return children for a given parent query

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ExtJs6: Ext.ComponentQuery.query('#autogenerated_id') returns an empty array if the component has an itemId

I have some ExtJs component.
I set itemId for it, but id is autogenerated.
Now Ext.getCmp('autogenerated-id') returns my component.
But Ext.ComponentQuery.query('#autogenerated-id') returns an empty array.
But:
Ext.ComponentQuery.query('[id=assets-information-form-1918]') again returns my component. :)
I use ExtJs 6.5.3 classic.
It seems like itemId config property hides autogenerated id from Ext.ComponentQuery, so they become mutually exclusive.
I don't need other means for search or advice to set id for the component, to write letter to Sencha support or to write post on their forum.
I need:
Means to force my Ext.ComponentQuery.query('#autogenerated-id') to
find the Component for which getId() returns 'autogenerated-id'.
If it is not possible by design, I need a link to some documentation
describing this behavior, a link to some bug report, or a filename and line number in ExtJs sources + a little snippet copy/paste from there.
From the documentation
Summary Provides searching of Components within Ext.ComponentManager
(globally) or a specific Ext.container.Container on the document with
a similar syntax to a CSS selector. Returns Array of matching
Components, or empty Array.
Ext.ComonpentQuery.query('#itemId') returns and array. Your cold above is using the auto-generated id of the component. The # indicates to query based on the component itemId and not the component id.
Try
Ext.ComponentQuery.query('assets-information-form-1918');
which will return an array, as noted in the documentation.
Ext.getCmp()
This is shorthand reference to Ext.ComponentManager#get. Looks up an
existing Ext.Component by id
Therefore it returns the component object.
Ext.ComponentQuery.query('#itemId')[0] would return the first object in the array.
Ext.ComponentQuery is the Sencha preferred method because it is more powerful when used as it does return an array so you an also query items by xtype and other attributes.

Get child node by name in Umbraco 7.8.1

My Content structure is:
-Home (the site root node)
-About Us
-Our Sevice1
-Our Sevice2
-Our Sevice3
I created a macro for Our Services.
In macro, I want Our Sevice1, Our Sevice2, Our Sevice3...
But in the list variable About Us also come but I don't want it
I want only our service name of the child node
var list= CurrentPage.Children();
About Us also come on the list but I don't want it.
The reason that you see the About Us page in the collection is because you use the Children method.
With the Children method you ask for the direct child nodes of a parent node traversing one level down. So in this case you ask for all direct children of the home page so this works like expected.
What you are trying to achieve is a collection of of all Service nodes. To accomplish this you could do something like this.
Make sure that you have a seperated Document Type for your service nodes ( like for example doc type Service Page ).
Then you can do the following:
var servicePages = CurrentPage.ServicePages;
You can view the docs about it here:
https://our.umbraco.org/documentation/reference/querying/dynamicpublishedcontent/collections
But all of this is using dynamic syntax, this will be removed in future versions of Umbraco. So I suggest you go and use the strongly type syntax.
Then this can be changed by:
var servicePages = Model.Content.Children.Where(x => x.DocmentTypeAlias == "servicePage");
What this does is take the IPublishedContent object of the current page you are on, which is the Home Page then you take all children which has a document type alias of type servicePage.
Like #Mivaweb mentioned, it's better to not use dynamics (I think for performance in addition to being removed in the future).
However, I don't think you have to create a separate doc type, although that will work too. The predicate for the Where method should handle other expressions such as:
var servicePages = Model.Content.Children.Where(x => x.Name.StartsWith("Our Sevice"));

Find pages with tag

In a Umbraco 7 solution, i have a Tags Content picker on all pages. Pages can with this, set tags on each page.
I then want to get alle pages, within the intire site, that has, lets say tag 111 (id, not name).
I have tried with:
var ids = Model.MacroParameters["tags"]; //the tags to show
CurrentPage.AncestorOrSelf(1).Descendants().Where(x => ids.Contains(x.tags.ToString()));
But that gives me the error:
Cannot use a lambda expression as an argument to a dynamically dispatched operation without first casting it to a delegate or expression tree type
Whats the correct way?
Solved it with;
Umbraco.Content(rootId).Descendants().Where("tags.Contains(#0)", ids);
You have a few options, depending on whether you prefer a dynamic or strongly typed view model.
Strongly Typed API
Umbraco.TypedContentAtRoot().Descendants().Where(x => x.tags.Contains(ids));
Dynamic API
Umbraco.ContentAtRoot().Descendants().Where("tags.Contains(#0)", ids);
Please note that the Contains statement may give you inconsistent results, as the tags property seems to be returning a comma separated list. In that case you can try splitting the string or install the Core Property Value Converters package and get the tags as IEnumerable<IPublishedContent>
Always try to avoid using Descendants, especially on the root node.
To get the tags for a property:
ApplicationContext.Current.Services.TagService.GetTagsForProperty(Model.Content.Id, "propertyname")
To find content with a specific tag:
ApplicationContext.Current.Services.TagService.GetTaggedContentByTag("tag")

how to set Personalizable attribute to generic list in webpart?

I develop web part with custom editor part and faced with this question.
Is it possible in web part set Personalizable attribute to generic List?
For example I want something like this:
[WebBrowsable(false)]
[Personalizable(PersonalizationScope.Shared)]
public List<AnnouncementItem> Announcements
{
get { return _announcements; }
set { _announcements = value; }
}
Is it possible, and what kind of types at all can be used as "Personalizable"?
Thanks.
Solution:
I use a custom EditorPart to select multiple lists using AssetUrlSelector, but I need a way to personalize this collection for end user.List<of custom objects> doesn't work, but I found that List<string> (and only string) work perfectly. So, I get required lists in EditorPart and pass their to the web part using List<string>.
Try using a custom EditorPart to add/remove items from the collection. I've never built a web part that personalized a collection so I don't know if it works but I'd definitely try the collection with an EditorPart. If it doesn't work, serialize XML into a string property.
Your question does not seem to match your code. Your code shows a collection of custom objects. I doubt an end user will be able to set such a property. To have a property that points to a generic list, you would probably be better off defining the property as a string that contains the URL to a list.

How to add / create Foul or bad language keyword filter in SharePoint Lists, Documents?

I am building an Internal social networking website on SharePoint. Since its a networking intranet, I want it to be Open and non moderated. However, I also dont want people to use abusive / Foul or bad language words in the portal.
I tried Googling and wasnt really sucessfull in finding a solution.
Microsoft Forefront will do that for me, but it only does for Documents. But I also want to do that on Lists since Discussion forum on the SharePoint is in a list format.
You may create site solution/list definition for your site using Visual studio Sharepoint Site Solution Genarator. Create a custom list and name it as you wish. I would name it "AbusiveWordList" in the following code example.
After creating site solution/list definition, Add below code in Item Adding function, which will iterate through all column in the list and will check from the custom list that is created named "AbusiveWordList". This list contains abusive words.
The chkbody function which will reference list item from custom list named "AbusiveWordList" and check if the bodytext contains item from AbusiveWordList.If yes, then it will throw an error.
*base.ItemAdding(properties);
foreach (DictionaryEntry
dictionaryEntry in
properties.AfterProperties) { string
bodytext = "";
bodytext = bodytext +
dictionaryEntry.Value;
finalwordcount = finalwordcount +
chkbody(bodytext, properties); }
if (finalwordcount > 0) {
properties.ErrorMessage = "Abusive /
Foul / Illicit information
found.Kindly refer to the terms and
conditions.";
properties.Cancel = true;
}
You will probably need to override any controls that display text to avoid this issue. As this would be a lot of work, perhaps an HTTP Module would be a better solution.
I've worked on a module that used regular expressions to make SharePoint's output XHTML compliant. Similarly, you could use regular expressions to strip out offensive words when a page is rendered. It wouldn't stop people typing them but as no-one would be able to see them this wouldn't matter. You could use a basic SharePoint custom list to store the offensive words you don't want displayed.

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