Set different font size to UIButton for different devices - ios

I have button called login. when i see the button font size it looks same in all the devices, though the button width and height vary. How to define different font size for different devices?. I am talking about only for iPhone portrait. So don't give solution as size class.

You can use font size variation - define size to font in Storyboard, look in below image it shows how to define size to font.
Click on small + button besides Font property, a pop up will appear.
As shown in above image you can define size for Width and Height for different variation.

Try this
if UIScreen.mainScreen().bounds.size.height == 480 {
// iPhone 4
mybutton.titleLabel.font = mybutton.titleLabel.font.fontWithSize(20)
} else if UIScreen.mainScreen().bounds.size.height == 568 {
// IPhone 5
mybutton.titleLabel.fontt = mybutton.titleLabel.font.fontWithSize(20)
} else if UIScreen.mainScreen().bounds.size.width == 375 {
// iPhone 6
mybutton.titleLabel.font = mybutton.titleLabel.font.fontWithSize(20)
} else if UIScreen.mainScreen().bounds.size.width == 414 {
// iPhone 6+
mybutton.titleLabel.font = mybutton.titleLabel.font.fontWithSize(20)
} else if UIScreen.mainScreen().bounds.size.width == 768 {
// iPad
mybutton.titleLabel.font = mybutton.titleLabel.font.fontWithSize(20)
}

You can check the iPhone device size and then in if-else loop apply your button font size logic.
#define iPhoneVersion ([[UIScreen mainScreen] bounds].size.height == 568 ? 5 : ([[UIScreen mainScreen] bounds].size.height == 480 ? 4 : ([[UIScreen mainScreen] bounds].size.height == 667 ? 6 : ([[UIScreen mainScreen] bounds].size.height == 736 ? 7 : ([[UIScreen mainScreen] bounds].size.height == 736 ? 61 : ([[UIScreen mainScreen] bounds].size.height == 736 ? 61 : (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad ? 10 :61 )))))))
if (iPhoneVersion == 4)
{
mybutton.titleLabel.font = [UIFont systemFontOfSize:12];
}
else if (iPhoneVersion == 5)
{
mybutton.titleLabel.font = [UIFont systemFontOfSize:14];
}
else if (iPhoneVersion == 6)
{
mybutton.titleLabel.font = [UIFont systemFontOfSize:16];
}
else if (iPhoneVersion == 7)
{
mybutton.titleLabel.font = [UIFont systemFontOfSize:17];
}
and same goes for all devices.

Related

Defining greater than for a iPhone 6 screen size?

I am using code which shows a certain xib file depending on the device, at the moment 3 xibs, one for iPhone4, one for iPhone5 and one for iPad.
Since iOS8 / iPhone 6, the app does not work on anything higher than the 5s due to the fact the xib does not know what to load;
- (IBAction)btnTapForStart:(id)sender {
fromOtherClass=YES;
if([[UIScreen mainScreen]bounds].size.height == 568)
{
PlayMusicViewController *pmvc = [[PlayMusicViewController alloc]initWithNibName:#"XibForIPhone5" bundle:[NSBundle mainBundle]];
[self.navigationController pushViewController:pmvc animated:YES];
}
else
{
PlayMusicViewController *pmvc = [[PlayMusicViewController alloc]init];
[self.navigationController pushViewController:pmvc animated:YES];
}
[appObject.audioPlayer stop];
}
If I change the value of 568 to higher it will work, but is there a way to combine it, for example, height is 568 OR iPhone6 size OR iPhone 6 plus size etc?
You probably should use auto-layout like Maddy says, but if you want to have code that works for specific devices, then you might want to implement this utility method. Then you can create as many xibs as you want and target them to specific devices. e.g.
if ([[Utilities deviceType] isEqualToString:#"iPhone Retina4"] || [[Utilities deviceType] isEqualToString:#"iPhone Retina35"] ) {
-- do something specific for these phones
}
I put this method in a Utilities class.
+ (NSString *)deviceType {
NSString *device = nil;
CGSize screenSize = [[UIScreen mainScreen] bounds].size;
CGFloat deviceScale = [UIScreen mainScreen].scale;
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
device = #"iPhone Classic"; // Just in case it doesn't make it through the conditionals
// Classic has a resolution of 480 × 320
if( (screenSize.height == 480 || screenSize.width == 480) && deviceScale == 1.0f ) {
device = #"iPhone Classic";
// Retina has a resolution of 960 × 640
} else if( (screenSize.height == 480 || screenSize.width == 480) && deviceScale == 2.0f ) {
device = #"iPhone Retina35";
// Retina 4" has a resolution of 1136 x 640
} else if (screenSize.height == 568 || screenSize.width == 568 ) {
device = #"iPhone Retina4";
// iPhone 6 has a resolution of 1334 by 750
} else if (screenSize.height == 667 || screenSize.width == 667 ) {
device = #"iPhone 6";
// iPhone 6 Plus has an actual size of 2208 × 1242 and resolution of 1920 by 1080
// Reported size is 736 x 414
} else if (screenSize.height == 736 || screenSize.width == 736 ) {
device = #"iPhone 6 Plus";
}
} else if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
device = #"iPad Classic"; // Just in case it doesn't make it through the conditionals
if(deviceScale == 1.0f) {
device = #"iPad Classic";
} else if (deviceScale == 2.0f) {
device = #"iPad Retina";
}
}
//NSLog(#"The device is %# scale is %f and the height is %f and width is %f", device, deviceScale, screenSize.height, screenSize.width);
return device;
}
I did some research on enums and they are nice. They make the code a bit more readable, but mostly they allow the compiler to help you type and catch errors. Xcode will autocomplete your deviceType for you and will give you the error: Use of undeclared identifier if you try to use a value that isn’t defined. Here’s the code rewritten as an enum. I prefixed the values with LF but you should use whatever is appropriate for your project.
This is in my header file
// Devices as of Fall 2014
typedef NS_ENUM(NSInteger, LFdeviceType) {
LFDeviceTypePhoneClassic,
LFDeviceTypePhoneRetina3_5,
LFDeviceTypePhoneRetina4,
LFDeviceTypePhone6,
LFDeviceTypePhone6Plus,
LFDeviceTypePadClassic,
LFDeviceTypePadRetina,
};
And this is in my .m file.
m+ (NSInteger)deviceType {
CGSize screenSize = [[UIScreen mainScreen] bounds].size;
CGFloat deviceScale = [UIScreen mainScreen].scale;
LFdeviceType device = LFDeviceTypePhoneClassic;
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
device = LFDeviceTypePhoneClassic; // Just in case it doesn't make it through the conditionals
// Classic has a resolution of 480 × 320
if( (screenSize.height == 480 || screenSize.width == 480) && deviceScale == 1.0f ) {
device = LFDeviceTypePhoneClassic;
// Retina has a resolution of 960 × 640
} else if( (screenSize.height == 480 || screenSize.width == 480) && deviceScale == 2.0f ) {
device = LFDeviceTypePhoneRetina3_5;
// Retina 4" has a resolution of 1136 x 640
} else if (screenSize.height == 568 || screenSize.width == 568 ) {
device = LFDeviceTypePhoneRetina4;
// iPhone 6 has a resolution of 1334 by 750
} else if (screenSize.height == 667 || screenSize.width == 667 ) {
device = LFDeviceTypePhone6;
// iPhone 6 Plus has an actual size of 2208 × 1242 and resolution of 1920 by 1080
// Reported size is 736 x 414
} else if (screenSize.height == 736 || screenSize.width == 736 ) {
device = LFDeviceTypePhone6Plus;
}
} else if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
device = LFDeviceTypePadClassic; // Just in case it doesn't make it through the conditionals
if(deviceScale == 1.0f) {
device = LFDeviceTypePadClassic;
} else if (deviceScale == 2.0f) {
device = LFDeviceTypePadRetina;
}
}
//NSLog(#"The device is %# scale is %f and the height is %f and width is %f", device, deviceScale, screenSize.height, screenSize.width);
return device;
}
Call it like this:
if ( ( [Utilities deviceType] == LFDeviceTypePhoneClassic
|| [Utilities deviceType] == LFDeviceTypePhoneRetina3_5) &&
numberOfFoilsOnScreen > 7 ) {
numberOfFoilsOnScreen = 7;
}

How can you tell if a user is using an iPhone 6 or 6+

Forgive me if this is a really stupid question I am just a beginner at all of this stuff. I want to make a separate interface for the iPhone 6 and 6 Plus but I don't know how the best way to be going about this is. This is a very simple app just to get myself more familiar with the language, etc. I was wondering if there is an easy way to tell if a user is using a 6 or 6 plus to make a separate interface for them. Thanks :)
Use single storyboard. Learn autolayout from raywanderlich, it think its a very good resource.
Also,now take advantage of the size classes introduced for ios 8 in xcode 6. This is called adaptive layout.
So instead of making the above four views for 3.5, 4, 4.7, 5.5 inch devices separately, and then worry about combining their respective landscape modes as well, just go for the 4 combination of size classes using auto layout (if possible, highly recommended) and relax for any other device size that may come into future.
To detect iPhone Version Please use below code.
if ([[UIScreen mainScreen] respondsToSelector:#selector(scale)]) {
if ([[UIScreen mainScreen] scale] == 2.0) {
if([UIScreen mainScreen].bounds.size.height == 667){
// iPhone retina-4.7 inch(iPhone 6)
}
else if([UIScreen mainScreen].bounds.size.height == 568){
// iPhone retina-4 inch(iPhone 5 or 5s)
}
else{
// iPhone retina-3.5 inch(iPhone 4s)
}
}
else if ([[UIScreen mainScreen] scale] == 3.0)
{
if([UIScreen mainScreen].bounds.size.height == 736.0){
//iPhone retina-5.5 inch screen(iPhone 6 plus)
}
}
}
Reference from Here
write this code in .pch file
#define IS_IPHONE_6 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 667.0)
#define IS_IPHONE_6_PLUS (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 736.0)
and wwhenever you need in any controller you simply check the condition.
Below are methods that do what you asked. One major thing to look out for is in iOS7 and below, when you check [[UIScreen mainScreen] bounds] for the screen bounds, it always lists the width and height as the same no matter what orientation the phone is in. So if it's an iPhone5 in landscape mode, it will still list the width as 320 and height as 568. In iOS8, this changed, now if that same iPhone5 is in landscape, it will list the width as 568 and the height as 320. Below are methods which account for this:
+ (BOOL) deviceHasFourInchScreen
{
return [DeviceType deviceHasScreenWithIdiom:UIUserInterfaceIdiomPhone scale:2.0 height:568.0];
}
+ (BOOL) deviceHasFourPointSevenInchScreen
{
return [DeviceType deviceHasScreenWithIdiom:UIUserInterfaceIdiomPhone scale:2.0 height:667.0];
}
+ (BOOL) deviceHasFivePointFiveInchScreen
{
return [DeviceType deviceHasScreenWithIdiom:UIUserInterfaceIdiomPhone scale:3.0 height:736.0];
}
+ (BOOL) deviceHasScreenWithIdiom:(UIUserInterfaceIdiom)userInterfaceIdiom scale:(CGFloat)scale height:(CGFloat)height
{
CGRect mainScreenBounds = [[UIScreen mainScreen] bounds];
CGFloat mainScreenHeight;
if ([OperatingSystemVersion operatingSystemVersionLessThan:#"8.0"])
{
mainScreenHeight = mainScreenBounds.size.height;
}
else
{
mainScreenHeight = (UIDeviceOrientationIsLandscape([[UIApplication sharedApplication] statusBarOrientation])) ? mainScreenBounds.size.width : mainScreenBounds.size.height;
}
if ([[UIDevice currentDevice] userInterfaceIdiom] == userInterfaceIdiom && [[UIScreen mainScreen] scale] == scale && mainScreenHeight == height)
{
return YES;
}
else
{
return NO;
}
}
Also here are the accompanying OperatingSystem class methods:
+ (NSString *) currentOperatingSystemVersion
{
return [[UIDevice currentDevice] systemVersion];
}
+ (BOOL) operatingSystemVersionLessThanOrEqualTo:(NSString *) operatingSystemVersionToCompare
{
return ([[self currentOperatingSystemVersion] compare: operatingSystemVersionToCompare options:NSNumericSearch] != NSOrderedDescending);
}
Put below lines in prefix.pch
#define iPhoneVersion ([[UIScreen mainScreen] bounds].size.height == 568 ? 5 : ([[UIScreen mainScreen] bounds].size.height == 480 ? 4 : ([[UIScreen mainScreen] bounds].size.height == 667 ? 6 : ([[UIScreen mainScreen] bounds].size.height == 736 ? 61 : 999))))
Now in programming you can say...
if (iPhoneVersion==4) {
NSLog("This is 3.5 inch iPhone - iPhone 4s or below");
} else if (iPhoneVersion==5) {
NSLog("This is 4 inch iPhone - iPhone 5 family");
} else if (iPhoneVersion==6) {
NSLog("This is 4.7 inch iPhone - iPhone 6");
} else if (iPhoneVersion==61) {
NSLog("This is 5.5 inch iPhone - iPhone 6 Plus.. The BIGGER");
} else {
NSLog("This is iPad");
}
However, I would say use one storyboard for all iPhones by learning autolayout.

Detect iPhone different resolution in iOS

I am using cocos2d in iOS .
I am having a problem detecting the iphone5 resolution(1136*640).
I am using code:
CGRect screenBounds = [[UIScreen mainScreen] bounds];
When we run app on iPhone simulator (4 inch), it gives screenWidth and screnHeight-320,480 respectively.
Can anyone tell me the solution for this?
Write this code in .m file.
#define WIDESCREEN ( fabs( ( double )[ [UIScreen mainScreen ]bounds ].size.height-( double )568 ) < DBL_EPSILON )
Now you can know the screen size like this.
if(WIDESCREEN)
{
NSLog(#"iPhone5 is here");
}
else
{
NSLog(#"iPhone4 is here");
}
you can add checks in your code for iPhone 4inch screens and 3.5 inch screens
CGSize result = [[UIScreen mainScreen] bounds].size;
if(result.height == 480)
{
// iPhone Classic
// set your frames for classic iPhone here
}
if(result.height == 568)
{
// iPhone 5, iPhone 5S, iPhone 5C
// set your frames for 4 inch iPhone here
}
iPhone 5 resolution is 1136*640 only. If you wanna check just Log below Code
the resolution it will give exactly (1136*640)
CGRect screenBounds = [[UIScreen mainScreen] bounds];
CGFloat screenScale = [[UIScreen mainScreen] scale];
CGSize screenSize = CGSizeMake(screenBounds.size.width * screenScale, screenBounds.size.height * screenScale);
NSLog(#"Screen SIze %#",NSStringFromCGSize (screenSize));
#define IS_IPHONE5 ([[UIScreen mainScreen] bounds].size.width >= 568 || [[UIScreen mainScreen] bounds].size.height >= 568)?YES:NO
#define IS_IPHONE4 ([[UIScreen mainScreen] bounds].size.width >= 480 || [[UIScreen mainScreen] bounds].size.height >= 480)?YES:NO
if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
{
if(IS_IPHONE4)
{
// iPhone 4
}
if(IS_IPHONE5)
{
// iPhone 5
}
}

Find device type iPhone 4 or iPhone5 not working [duplicate]

This question already has answers here:
How to detect iPhone 5 (widescreen devices)?
(24 answers)
Closed 9 years ago.
if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone){
CGSize result = [[UIScreen mainScreen] bounds].size;
//NSLog(#"phonesize%#",result);
if(result.height > 500){
NSLog(#"iPhone 5");
}
else{
NSLog(#"iPhone 4");
}
}
My Mac OS is 10.7.2 and Xcode 4.5.2.I used above code to find device is iPhone 4 or iPhone 5
It is giving iPhone4 when i uses iPhone5.I did set launch image and icon image. Is there anything else i missed out?
Make sure you have a PNG file named Default-568h#2x.png in your project.
You need to scale the result you got as per the screen's scale scale and then check ...
if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone){
if ([[UIScreen mainScreen] respondsToSelector: #selector(scale)]) {
CGSize result = [[UIScreen mainScreen] bounds].size;
CGFloat scale = [UIScreen mainScreen].scale;
result = CGSizeMake(result.width * scale, result.height * scale);
if(result.height == 960) {
NSLog(#"iPhone 4");
}
if(result.height == 1136) {
NSLog(#"iPhone 5");
}
}
else{
NSLog(#"Standard Resolution");
}
}
Try this code instead its tested.
if ([[UIDevice currentDevice] userInterfaceIdiom] ==UIUserInterfaceIdiomPhone)
{
//device is iPhone
CGRect screenBounds = [[UIScreen mainScreen] bounds];
if (screenBounds.size.height == 568) {
//device is iphone 5
//add storyboard/Xib that have large screen (320*568)
} else {
//device is iphone 4
//add story board/Xib that have small screen (320*480)
}
}
else
{
//device is iPad
}
if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
{
CGRect screenBounds = [[UIScreen mainScreen] bounds];
if (screenBounds.size.height == 568)
{
//iphone 5
else
{
//iphone 4
}
}
else
{
//iPad
}
Try this one might be helpful to you...

coding for iphone 5 screen

I have taken a universal project. I have coded for iPhone 5 screen but it doesn't detect it.
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
//ui for ipad
}
else if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
CGRect screenBounds = [[UIScreen mainScreen] bounds];
if (screenBounds.size.height == 568) {
tableView.frame = CGRectMake(0, 40, 320 ,508);
}
else {
tableView.frame = CGRectMake(0, 40, 320 ,420);
}
}
It doesn't work though. When I debug the code on iPhone 5 screenBounds = 320*480.
Where am I going wrong?
It is so simple to detect iPhone5 screen,
Just write
#define IS_IPHONE5 (([[UIScreen mainScreen] bounds].size.height-568)?NO:YES)
in your .pch file.... and you can further check for iPhone5 screen like if(IS_IPHONE5).
Choose your UITableView from the IB and select the size as Retina 4 for all screens, even the main window xib file. This works fine even on the iphone 4.
you add Splash Screen for iphone 5.Default-568h#2x.png file then its work fine
This code works fine for me
#define IS_IPHONE_5 ( fabs( ( double )[ [ UIScreen mainScreen ] bounds ].size.height - ( double )568 ) < DBL_EPSILON )
if (IS_IPHONE_5)
   {
//iphone 5
}
Try using this to detect iPhone 5 instead:
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
{
CGSize theHeight = [[UIScreen mainScreen] bounds].size;
if(theHeight.height == 568) {
// iPhone 5
tableView.frame = CGRectMake(0, 40, 320 ,508);
}
else {
// iPhone 4
tableView.frame = CGRectMake(0, 40, 320 ,420);
}
}
Alternatively you can define this:
#define IS_IPHONE5 (([[UIScreen mainScreen] bounds].size.height-568)?NO:YES)
Which you can re-use whenever you need to find out if it's iPhone 5 or not.
Try this code ::
if ([[UIScreen mainScreen] bounds].size.height == 568)
{
[tableView setFrame:CGRectMake(0, 40, 320 ,508)];
}
else if ([[UIScreen mainScreen] bounds].size.height == 480)
{
[tableView setFrame:CGRectMake(0, 40, 320 ,420)];
}
Hope, it'll help you.
Thanks.
I used this code to check iPhone 5 device.
float scrnheight = [[UIScreen mainScreen] bounds].size.height ;
if(scrnheight == 568.0f)
{
self.isIphone5 = true;
}

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