Why is javac telling me illegal start of expression? - javac

Question

Here's my code, i do not know what I'm doing wrong seriously. I tried many different things like taking the public modifier away from get. but I still get the same thing. This program is supposed to print out the Nth number line in the pascal triangle do to that I am using recursion a little bit.
import java.util.*;
public class Triangle{
private int lineNumber, count;
private int[] num;
public Triangle(){
lineNumber = 1;
}
public Triangle(int n){
set(n);
}
public void set(int n){
if(n < 1){
lineNumber = 1;
}
else{
lineNumber = n;
}
public int get()//Triangle.java:26: error: ';' expected //
{
return lineNumber;
}
private void pascal(int[] row){ //Triangle.java:30: error: illegal start of expression
if(count >= lineNumber){
return;
}
num = new int[row.length + 1];
num[0] = 1;
for(int i = 1; i < row.length; i++){
num[i] = row[i - 1] + row[i];
}
num[row.length] = 1;
count ++;
pascal(num);
return;
}
public int[] output(){
count = 1;
num = new int[count];
num[0] = 1;
pascal(num);
return num;
}
public static void main(String[] args){
int i,userNum;
Scanner scnr = new Scanner(System.in);
System.out.println("Enter a number to get the nth line of"+
" Pascal's Triangle." );
userNum = input.nextInt();
PascalTriangle triangle = new Triangle(userNum);
int[] result = triangle.output();
System.out.println("\n Line " + triangle.get() + " of "
+ "Pascal's Triangle is ");
for(i = 0; i < result.length; i++){
System.out.println(result[i] + " ");
}
}
}
}

Answer 1

You need one more closing bracket after the else statement in the set() method.Try to add the closing } before
else{
lineNumber = n;
}
}
public int get()//Triangle.java:26: error: ';' expected //