How can I combine these two arrays in to a hash. They may be of equal sizes or not.
#status_array = ["ready", "required", "processing", "approval", "live"]
#part_milestones = [#<Milestone id: 657707, data_type: "ready">, #<Milestone id: 657708, data_type: "required">, #<Milestone id: 657709, data_type: "approval">]
They are sorted already. I just need the hash to deal with the "blanks" properly like so:
{"ready"=>#<Milestone id: 657707, data_type: "ready">, "required"=>#<Milestone id: 657708, data_type: "required">, "processing"=>nil, "approval"=>#<Milestone id: 657709, data_type: "approval">, "live"=>nil}
The cleanest way I know to do this is:
hash = #status_array.inject({}) do |result_hash, status|
result_hash[status] = #part_milestones.select { |milestone| milestone.data_type == status }.first
result_hash
end
You can use zip to merge the arrays into two dimensional and then use the following to convert into hash
Hash[#status_array.zip(#part_milestones)]
Documentation for Hash[]
UPDATE:
just realized that its not a one to one mapping
hash = {}
#status_array.each do |status|
hash[status] = #part_milestone.find{|milestone| milestone.data_type == status}
end
#part_milestones.sort_by &:data_type should do the trick
Related
I have to remove the 'Other' Category from the array, which is originally sorted alphabetically, and just make it the last index. I created this little helper but believe there could be a faster way of accomplishing this.
The array is something like this [#<Category id: 17, title: "Books">, #<Category id: 18, title: "Children's Clothing">,
Here is what I've done. It works. Although, I was wonder if theres a more efficient way.
<%
#options = []
#other_option = []
#free_item_options.each do |category|
if category.title.downcase == "other"
#other_option << category
else
#options << category
end
end
#options << #other_option[0]
%>
In cases like this, I usually reach for multi-parameter sorting.
#free_item_options.sort_by do |option|
[
option.title.casecmp?('other') ? 1 : 0,
option.title,
]
end
"Other" category will have 1 and will sort last. Everything else will have 0 and will sort between themselves by ascending title.
Another approach is to just use SQL.
#free_item_options = Category.select("categories.*, (LOWER(title) = 'other') as is_other").order('is_other', :title).to_a
There is Enumerable#partition which is designed to split a collection up in two partitions.
#other_option, #options = #free_item_options.partition { |category| category.title.casecmp?('other') }
#options.concat(#other_options)
If you are certain there is a maximum of one "other" category (which seems to be the case based upon #options << #other_option[0]). You could also use find_index in combination with delete_at and <<. find_index stops iterating upon the first match.
index = #free_item_options.find_index { |category| category.title.casecmp?('other') }
#free_item_options << #free_item_options.delete_at(index) if index
Keep in mind the above does mutate #free_item_options.
I am trying to convert one of my array into some format where it can convert itself into table format.
I have an array which is:
[
{
id: 1,
Revenue_Account: "Revenue Receipt",
Amount: 59567,
Year: "2012-13",
created_at: "2018-08-21T06:30:17.000Z",
updated_at: "2018-08-21T06:30:17.000Z"
},
{
id: 2,
Revenue_Account: "Revenue Expenditure ",
Amount: 54466,
Year: "2012-13",
created_at: "2018-08-21T06:30:17.000Z",
updated_at: "2018-08-21T06:30:17.000Z"
},
...
]
Full code of my array link to my actual array
I want this data to be converted into this format:
data: [
{
id: 1,
Sector: "Revenue Receipt",
2012-13: 59567,
2013-14: 68919,
2014-15: 72570,
2015-16: 96123,
2016-17: 105585,
2017-18_BE: 137158,
},
{
id: 2,
Sector: "Revenue Expenditure",
2012-13: 59567,
2013-14: 68919,
2014-15: 72570,
2015-16: 96123,
2016-17: 105585,
2017-18_BE: 137158,
},
....
]
I am using this code to group my array:
group = b.group_by{|data| data[:Revenue_Account]}
this is grouping my data as I am expecting in order to achieve my goal I am trying this code.
group = b.group_by{|data| data[:Revenue_Account]}
du = []
group.each do |i|
du.push({Sector:i[0]})
end
This is giving me Sector wise result how can I add year in my code.
You can't have a single id in there because you're grouping up many entries with different ids, but this is how you'd get the array in the format you're asking for:
grouped = {}
b.each do |x|
grouped[x[:Revenue_Account]] ||= {}
grouped[x[:Revenue_Account]][:Sector] = x[:Revenue_Account]
grouped[x[:Revenue_Account]][x[:Year]] = x[:Amount]
end
return {data: grouped.values}
Which gets you:
{
:data=>[
{
:Sector=>"Revenue Receipt",
"2012-13"=>59567,
"2013-14"=>68919,
"2014-15"=>78417,
"2015-16"=>96123,
"2016-17"=>105585,
"2017-18_BE"=>137158
},
{
:Sector=>"Revenue Expenditure ",
"2012-13"=>54466,
"2013-14"=>62477,
"2014-15"=>72570,
"2015-16"=>83616,
"2016-17"=>94765,
"2017-18_BE"=>122603
},
]
}
We build a new hash by looping through the original hash and creating hash keys if they don't exist. Then we start assigning values as you want them to be in the output. On each iteration, we're creating a new key in this hash for the Revenue_Account value if its the first time we've seen it. Then we assign that particular Revenue_Account's Date and Amount to the output. So for value 'Revenue Receipt' it looks like this:
Grouped hash starts off as empty
On first iteration, we see that group["Revenue Receipt"] is nil, so we initialize it with an empty hash via ||= (assign if nil)
We then assign :Sector => "Revenue Receipt" and this entry's Year and Amount, "2012-13" => 59567
Our grouped hash looks like: {"Revenue Receipt" => {:Sector => "Revenue Receipt", "2012-13" => 59567}
On the next iteration we see that group["Revenue Receipt"] is not nil, so ||= does not override it with an empty hash
We then assign :Sector => "Revenue Receipt" and this entry's Year and Amount, "2012-14" => 68919, which adds a new key/value to the existing hash
Our grouped hash now looks like: {"Revenue Receipt" => {:Sector => "Revenue Receipt", "2012-13" => 59567, "2012-14" => 68919}
After we parse the entire array, we now have a hash that has a key of the Revenue_Account, and values which look like the hash output you're expecting.
We discard the key and return only the hash values, which gets you the final output.
Another option, directly manipulating the array.
array_of_data = array
.each { |h| h[:Sector] = h.delete(:Revenue_Account) }
.each { |h| h[h[:Year]] = h[:Amount]}
.each { |h| h.delete_if{ |k, _| k == :created_at || k == :updated_at || k == :id || k == :Year || k == :Amount} }
.group_by { |h| h[:Sector] }
.values.map { |a| a.inject(:merge) }
Then just:
h = {}
h[:data] = array_of_data
To understand what happens along the code, just ad line by line outputting the result, like:
p array
.each { |h| h[:Sector] = h.delete(:Revenue_Account) }
Then:
p array
.each { |h| h[:Sector] = h.delete(:Revenue_Account) }
.each { |h| h[h[:Year]] = h[:Amount]}
Etcetera...
To understand .inject(:merge), see here Rails mapping array of hashes onto single hash
I have an array and it has many columns and I want to change one value of my one column.
My array is:
[
{
id: 1,
Districts: "Lakhisarai",
Area: 15.87,
Production: 67.77,
Productivity: 4271,
Year: 2015,
Area_Colour: "Red",
Production_Colour: "Orange",
Productivity_Colour: "Dark_Green",
created_at: "2018-07-24T11:24:13.000Z",
updated_at: "2018-07-24T11:24:13.000Z"
},
{
id: 29,
Districts: "Begusarai",
Area: 18.53,
Production: 29.35,
Productivity: 1584,
Year: 2015,
Area_Colour: "Red",
Production_Colour: "Red",
Productivity_Colour: "Orange",
created_at: "2018-07-24T11:24:13.000Z",
updated_at: "2018-07-24T11:24:13.000Z"
},
...
]
This is my sample array and I want my Productivity to be divided by 100 for that I am using one empty array and pushing these hashes to my array like:
j = []
b.map do |k|
if k.Productivity
u = k.Productivity/100
j.push({id: k.id, Productivity: u })
else
j.push({id: k.id, Productivity: k.Productivity })
end
Is there any simple way where I can generate this kind of array and reflect my changes to to one column. Is there any way where I don't need to push name of column one by one in push method.
I want to generate exact same array with one modification in productivity
let's say your array is e, then:
e.each { |item| item[:Productivity] = item[:Productivity]/100}
Example:
e = [{p: 12, d: 13}, {p:14, d:70}]
e.each { |item| item[:p] = item[:p]/10}
output: [{:p=>1, :d=>13}, {:p=>1, :d=>70}]
You could take help of map method here to create a new array from your original array, but with the mentioned changes.
ary.map do |elem|
h = elem.slice(:id)
h[:productivity] = elem[:Productivity] / 100 if elem[:Productivity]
h
end
=> [{:id=>1, :productivity=>42}, {:id=>29, :productivity=>15}]
Note, Hash#slice returns a new hash with only the key-value pairs for the keys passed in argument e.g. here, it returns { id: 1 } for first element.
Also, we are assigning the calculated productivity to the output only when it is set on original hash. Hence, the if condition there.
I have an array of hash.
eg) array_of_hash = [ { id: 20, name: 'John' }, { id: 30, name: 'Doe'} ]
I would like to get records which match all the criteria in a particular hash.
So the query I want to get executed is
SELECT persons.* FROM persons WHERE persons.id = 20 AND persons.name = 'John' OR persons.id = 30 AND persons.name = 'Doe'
What is the best way to construct this query from an array of hash?
I think this is okay:
ids = array_of_hash.map { |h| h[:id] }
names = array_of_hash.map { |h| h[:name] }
Person.where(id: ids, name: names)
(although it's not super generic)
other attempt:
people = Person.all
array_of_hash.each do |h|
people = people.where(h)
end
people # => will generate a long long query.
Try to map all conditions to your ActiveRecord model independently and flatten the result array afterwards:
array_of_hash.map{ |where_clause| Person.where(where_clause) }.flatten
Lets say I have an Array of content_categories (content_categories = user.content_categories)
I now want to add every element belonging to a certain categorie to content_categories with the category as a key and the the content-item IDs as elements of a set
In PHP something like this is possible:
foreach ($content_categories as $key => $category) {
$contentsByCategoryIDArray = Category.getContents($category[id])
$content_categories[$key][$contentsByCategoryIDArray]
}
Is there an easy way in rails to do this?
Greets,
Nico
Your question isn't really a Rails question, it's a general Ruby programming question.
Your description isn't very clear, but from what I understand, you want to group IDs for common categories using a Hash. There are various other ways of doing this, but this is easy to understand::
ary = [
'cat1', {:id => 1},
'cat2', {:id => 2},
'cat1', {:id => 3}
]
hsh = {}
ary.each_slice(2) { |a|
key,category = a
hsh[key] ? hsh[key] << category[:id] : hsh[key] = [category[:id]]
}
hsh # => {"cat1"=>[1, 3], "cat2"=>[2]}
I'm using a simple Array with a category, followed by a simple hash representing some object instance, because it makes it easy to visualize. If you have a more complex object, replace the hash entries with those objects, and tweak how you access the ID in the ternary (?:) line.
Using Enumerable.inject():
hsh = ary.each_slice(2).inject({}) { |h,a|
key,category = a
h[key] ? h[key] << category[:id] : h[key] = [category[:id]]
h
}
hsh # => {"cat1"=>[1, 3], "cat2"=>[2]}
Enumerable.group_by() could probably shrink it even more, but my brain is fading.
I'd use Enumerable#inject
content_categories = content_categories_array.inject({}){ |memo, category| memo[category] = Category.get_contents(category); memo }
Hash[content_categories.map{|cat|
[cat, Category.get_contents(cat)]
}]
Not really the right answer, because you want IDs in your array, but I post it anyway, because it's nice and short, and you might actually get away with it:
content_categories.group_by(&:category)
content_categories.each do |k,v|
content_categories[k] = Category.getContents(v)
end
I suppose it's works
If i understand correctly, content_categories is an array of categories, which needs to be turned into a hash of categories, and their elements.
content_categories_array = content_categories
content_categories_hash = {}
content_categories_array.each do |category|
content_categories_hash[category] = Category.get_contents(category)
end
content_categories = content_categories_hash
That is the long version, which you can also write like
content_categories = {}.tap do |hash|
content_categories.each { |category| hash[category] = Category.get_contents(category) }
end
For this solution, content_categories must be a hash, not an array as you describe. Otherwise not sure where you're getting the key.
contents_by_categories = Hash[*content_categories.map{|k, v| [k, Category.getContents(v.id)]}]