I have gone through msdn article, read whitepaper on number sequences and made number sequences a lot many times. But in this scenario I need some help.
Scenario is; I want to get next sequence number through x++ code using just number sequence code and no reference etc.
I have tried following (and many others but this is nearest solution) ;
static void myTestJob(Args _args)
{
NumberSeq num;
num = NumberSeq::newGetNumFromCode('SAO-Y');
info(num.num()) ;
}
It generates number sequence against some number sequence codes, but for other it throws error that;
"Number sequence does not exist."
I have tried many other options mentioned on many other blogs and tried to explore AX as well, but now need some assistance.
P.S. I'm not creating number sequence using x++ code but from front end (organization administration).
I am able to suppress the exception by using following;
num = NumberSeq::newGetNumFromCode(<<someNumberSequenceCode>>, NumberSeqScopeFactory::createDefaultScope(), true, true);
As, fourth optional parameter of NumberSeq::newGetNumFromCode(,,,true); says not to throw exception on missing reference.
boolean _dontThrowOnMissingRefSetUp = false,
As I said earlier, I have created number sequence from organization administration without writing any code (EDT, class, parameters table etc. stuff) so no reference was generated and I think I was getting exception due to this.
Please have a look at your number sequence that you have set up. I recon it has something to do with the numbersequence scope.
Make sure the scope of the number sequence is valid within the company you are calling this.
It's work, but not raice result: Voucher not generated.
Working way:
num = NumberSeq::newGetNumFromCode(<<someNumberSequenceCode>>,
NumberSeqScopeFactory::createDefaultScope(), **false**, true);
When my Number Sequence - Scope is setup as Shared I can use this code:
numSequence = NumberSeq::newGetNumFromCode(<<someNumberSequenceCode>>, NumberSeqScopeFactory::createDataAreaScope(curext()), true, true);
When my Number Sequence - Scope is setup as Company I can use this code:
numSequence = NumberSeq::newGetNumFromCode(<<someNumberSequenceCode>>);
Related
Consider this F# code:
let isSalary employee =
let (fName,lName,Occupation,Department,SalaryType,
HoursPerWeek, AnnualSalary, HourlyWage
) = employee
SalaryType = "Salary"
if(employee.SalaryType = SalaryType) then
true
else
false
Im getting errors in here, any fixes to it?
First things first, please post error messages and a much more specific question. Thanks! But luckily, I can about deduce the error messages from this problem.
Next, if you want to mutate SalaryType after you've deconstructed your employee 8-tuple, you should write using the mutable keyword:
let mutable (fName, lName, Occupation, Department, SalaryType,
HoursPerWeek, AnnualSalary, HourlyWage) = employee
But you shouldn't. This is explained further below.
Next problem: there is no dot notation (no tuple.member) for accessing members of a tuple. It's only possible through deconstruction. So you can't employee.SalaryType.
Here's what looks to be the crux of the problem, and it's a mistake I made many times when I was learning functional programming, and it's a difficult paradigm shift to adapt to. You should not be attempting to mutate data, or in this case, variables. Variables, or values as they are called in F#, shouldn't change, as a broad rule. Functions should be pure.
What this means is that any parameters you pass into a function should not change after leaving the function. The parameter employee should be the same after you return to the calling scope.
There's a few syntactical errors you've made that make it pretty much impossible for me to deduce what you're trying to do in the first place. Please include this in the question.
Also, one last nitpick. As you know, the last expression in an F# function is it's return value. Instead of using an if statement, just return the condition you're testing, like this:
let ...
...
employee.SalaryType = SalaryType <- but remember, you can't use dot notation on tuples; this is just an example
Please read more on
https://learn.microsoft.com/en-us/dotnet/fsharp/language-reference/
I know the lexical analyser tokenizes the input and stores it in a stream, or at least that is what I understood. Unfortunately nearly all articles I have read only talk about lexing simple expressions. What I am interested in is how to tokenize something like:
if (fooBar > 5) {
for (var i = 0; i < alot.length; i++) {
fooBar += 2 + i;
}
}
Please note that this is pseudo code.
Question: I would like to know how the data structure looks like for tokens created by the lexer? I really have no idea for the example i gave above where code is nested. Some example would be nice.
First of all, tokens are not necessarily stored. Some compilers do store the tokens in a table or other data structure, but for a simple compiler (if there is such a thing) it's sufficient in most cases that the lexer can return the type of the next token to be parsed and then in some cases the parser might ask the lexer for the actual text that the token is made up of.
If we use your sample code,
if (fooBar > 5) {
for (var i = 0; i < alot.length; i++) {
fooBar += 2 + i;
}
}
The type of the first token in this sample might be defined as TOK_IF corresponding to the "if" keyword. The next token might be TOK_LPAREN, then TOK_IDENT, then TOK_GREATER, then TOK_INT_LITERAL, and so on. What exactly the types should be is defined by you as the author of the lexer (or tokenizer) code. (Note that there are about a million different tools to help you avoid the somewhat tedious task of coming up with these details by hand.)
Except for TOK_IDENT and TOK_INT_LITERAL the tokens we've seen so far are defined entirely by their type. For these two, we would need to be able to ask the lexer for the underlying text so that we can evaluate the value of the token.
So a tiny excerpt of the parser dealing with an IF statement in pseudo-code might look something like:
...
switch(lexer.GetNextTokenType())
case TOK_IF:
{
// "if" statement
if (lexer.GetNextTokenType() != TOK_LPAREN)
throw SyntaxError('( expected');
ParseRelationalExpression(lexer);
if (lexer.GetNextTokenType() != TOK_RPAREN)
throw SyntaxError(') expected');
...
and so on.
If the compiler did choose to actually store the tokens for later reference, and some compilers do e.g. to allow for more efficient backtracking, one way would be to use a structure similar to the following
struct {
int TokenType;
char* TokenStart;
int TokenLength;
}
The container for these might be a linked list or std::vector (assuming C++).
I'm maintaining someone else's Lua code, and Lua is not my preferred language. This is probably a complete noob question, but I can't seem to find the answer on Google or SO...
The following code
if !(v.LastHealth == v:Health()) then
local newColor = {}
newColor.r = v.orgColor.r - (v.orgColor.r - curColor.r) --This is the line the error occurs on
newColor.g = v.orgColor.g - (v.orgColor.g * clrPercent)
newColor.b = v.orgColor.b - (v.orgColor.b * clrPercent)
newColor.a = v.orgColor.a - (v.orgColor.a - curColor.a)
v:SetColor( newColor )
produces the error
attempt to perform arithmetic on field 'r' (a table value)
orgColor (maybe, not totally certain- v.orgColor may be an outdated thing) and curColor are tables that have entries (Uh. I think. bla.x is the same as bla[x] in Lua, right?) r, g, b, and a. Apparently I can't do math on things that come from tables? Should I stow all these values in local variables before working with them? That doesn't seem right.
EDIT:
Printing v.orgColor gives table: 0x40390080, which I assume means it exists and is a table. What's odd is, v.orgColor.r gives another table! That sounds like the cause.
As it turns out, v.orgColor was not, as I had presumed, set by the host program, but was set by the same script as the code sample is from. There was an API change that made a function that used to return four RGBA values instead return a table of those same values; the old code set orgColor.r to the table containing those values, causing the error.
Moral of the story, I suppose, is that you should always make sure you know what's setting the variables you're working with.
I'm actually using Z3py for scheduling solving problems and I'm trying to represent a 2 processors system where 4 process of different execution time must be done.
My actual data are :
Process 1 : Arrival at 0 and execution time of 4
Process 2 : Arrival at 1 and execution time of 3
Process 3 : Arrival at 3 and execution time of 5
Process 4 : Arrival at 1 and execution time of 2
I'm actually trying to represent each process while decomposing each in subprocess of equal time so my datatypes are like this :
Pn = Datatype('Pn')
Pn.declare('1')
Pn.declare('2')
Pn.declare('3')
Pn.declare('4')
Pt = Datatype('Pt')
Pt.declare('1')
Pt.declare('2')
Pt.declare('3')
Pt.declare('4')
Pt.declare('5')
Process = Datatype('Process')
Process.declare('cons' , ('name',Pn) , ('time', Pt))
Process.declare('idle')
where pn and pt are the process name and the part of the process (process 1 is in 4 parts, ...)
But now I don't know how I can represent my processors to add 3 rules I need : unicity (each sub process must be done 1 and only 1 time by only 1 processor) check arrival (the first part of a process can't be processed before it arrived) and order (each part of a process must be processed after the precedent)
So I was thinking of using arrays to represent my 2 processors with this kind of declaration :
P = Array('P', IntSort() , Process)
But when I tried to execute it I got an error message saying :
Traceback (most recent call last):
File "C:\Users\Alexis\Desktop\test.py", line 16, in <module>
P = Array('P', IntSort() , Process)
File "src/api/python\z3.py", line 3887, in Array
File "src/api/python\z3.py", line 3873, in ArraySort
File "src/api/python\z3.py", line 56, in _z3_assert
Z3Exception: 'Z3 sort expected'
And know I don't know how handle it... must I create a new datatype and figure a way to add my rules ? or Is there a way to add datatypes to array which would let me create rules like this :
unicity = ForAll([x,y] , (Implies(x!=y,P[x]!=P[y])))
Thanks in advance
There is a tutorial on using Datatypes from the Python API. A link to the tutorial is:
http://rise4fun.com/Z3Py/tutorialcontent/advanced#h22
It shows how to create a list data-type and use the "create()" method to instantiate a Sort object from the object used when declaring the data-type. For your example, it suffices to add calls to "create()" in the places where you want to use the declared type as a sort.
See: http://rise4fun.com/Z3Py/rQ7t
Regarding the rest of the case study you are looking at: it is certainly possible to express the constrsaints you describe using quantifiers and arrays. You could also consider somewhat more efficient encodings:
Instead of using an array, use a function declaration. So P would be declared as a unary function:
P = Function('P', IntSort(), Process.create()).
Using quantifiers for small finite domain problems may be more of an overhead than a benefit. Writing down the constraints directly as a finite conjunction saves the overhead of instantiating quantifiers possibly repeatedly. That said, some quantified axioms can also be optimized. Z3 automatically compiles axioms of the form: ForAll([x,y], Implies(x != y, P(x) != P(y))) into
an axioms of the form Forall([x], Pinv(P(x)) == x), where "Pinv" is a fresh function. The new axiom still enforces that P is injective but requires only a linear number of instantiations, linear in the number of occurrences of P(t) for some term 't'.
Have fun!
Could someone please tell me how to write a custom function in Open Office Basic to be used in Open Office Calc and that returns an array of values. An example of one such built-in function is MINVERSE. I need to write a custom function that populates a range of cells in much the same way.
Help would be much appreciated.
Yay, I just figured it out: all you do is return an array from your macro, BUT you also have to press Ctrl+Shift+Enter when typing in the cell formula to call your function (which is also the case when working with other arrays in calc). Here's an example:
Function MakeArray
Dim ret(2,2)
ret(0,0) = 1
ret(1,0) = 2
ret(0,1) = 3
ret(1,1) = 4
MakeArray = ret
End Function
FWIW, damjan's MakeArray function returns a Variant containing an array, I think. (The type returned by MakeArray is unspecified, so it defaults to Variant. A Variant is a container with a descriptive header, apparently cast as needed by the interpreter.)
Almost, but not quite, the same thing as returning an array. According to http://www.cpearson.com/excel/passingandreturningarrays.htm, Microsoft did not introduce the ability to return an array until 2000. His example [ LoadNumbers(Low As Long, High As Long) As Long()] does not compile in OO, flagging a syntax error on the parens following Long. It appears that OO's Basic emulates the pre-2k VBA.