How can I convert a string like s = "6.1101,17.592,3.3245\n" to numbers in Lua.
In python, I usually do
a = s.strip().split(',')
a = [float(i) for i in a]
What is the proper way to do this with Lua?
This is fairly trivial; just do a repeated match:
for match in s:gmatch("([%d%.%+%-]+),?") do
output[#output + 1] = tonumber(match)
end
This of course assumes that there are no spaces in the numbers.
Related
im trying to make locals with Chinese letters
local 屁 = p
or
屁 = p
none of those work
any ways to do it?
You can't do this as "屁" is not a valid Lua identifier.
Lua identifiers can only have letters, numbers and underscores and must not start with a number.
However, you can create a table with a key 屁:
local chinese_letters = {
["屁"] = p
}
And access it as chinese_letters["屁"], for example
local chinese_letters = {
["屁"] = 10
}
print(chinese_letters["屁"])
By the way, the correct name for these chinese characters is Hanzi
as a followup question to lua tables - allowed values and syntax:
I need a table that equates large numbers to strings. The catch seems to be that strings with punctuation are not allowed:
local Names = {
[7022003001] = fulsom jct, OH
[7022003002] = kennedy center, NY
}
but neither are quotes:
local Names = {
[7022003001] = "fulsom jct, OH"
[7022003002] = "kennedy center, NY"
}
I have even tried without any spaces:
local Names = {
[7022003001] = fulsomjctOH
[7022003002] = kennedycenterNY
}
When this module is loaded, wireshark complains "}" is expected to close "{" at line . How can I implement a table with a string that contains spaces and punctuation?
As per Lua Reference Manual - 3.1 - Lexical Conventions:
A short literal string can be delimited by matching single or double quotes, and can contain the (...) C-like escape sequences (...).
That means the short literal string in Lua is:
local foo = "I'm a string literal"
This matches your second example. The reason why it fails is because it lacks a separator between table members:
local Names = {
[7022003001] = "fulsom jct, OH",
[7022003002] = "kennedy center, NY"
}
You can also add a trailing separator after the last member.
The more detailed description of the table constructor can be found in 3.4.9 - Table Constructors. It could be summed up by the example provided there:
a = { [f(1)] = g; "x", "y"; x = 1, f(x), [30] = 23; 45 }
I really, really recommend using the Lua Reference Manual, it is an amazing helper.
I also highly encourage you to read some basic tutorials e.g. Learn Lua in 15 minutes. They should give you an overview of the language you are trying to use.
How would I extract every number from a string and put them in an array?
For example the string:
"\113\115\106\111\117\41\40\105\102\109\109\112\40\42"
You can use string.gmatch like this:
local my_array = {}
local my_string = "\\113\\115\\106\\111\\117\\41\\40\\105\\102\\109\\109\\112\\40\\42"
print(my_string) --note how the string is \ followed by digits
for number in string.gmatch(my_string, "\\(%d+)") do
my_array[#my_array + 1] = tonumber(number)
print(number)
end
This will get you an table with all the numbers from your string.
The \ is escaped in my example to make it equal to the string you stated.
If i misunderstood your question and the numbers you want are from the chars then you need to do
local my_array = {}
local my_string = "\113\115\106\111\117\41\40\105\102\109\109\112\40\42"
print(my_string) --note how the string is letters
for char in string.gmatch(my_string, ".") do
my_array[#my_array + 1] = string.byte(char)
print(char, my_array[#my_array])
end
My string is
text1,text2
I want to split text1 and text2 by using the ','.
Try this:
s="text1,text2"
t1,t2=s:match("(.-),(.-)$")
print(t1,t2)
To get an iterator with the substrings, you can call string.gmatch.
for i in string.gmatch(example, "%P+") do
print(i)
end
To just get them into two separate strings, you can just call the iterator;
> iter = string.gmatch(indata, "%P+")
> str1 = iter()
> str2 = iter()
> print (str1)
test1
> print (str2)
test2
If you want them stored in an array instead, there's a whole discussion here how to achieve that.
#lhf added a better pattern [^,]+ in the comments, mine splits on any punctuation, his only on comma.
Try the functions given in this page:
http://lua-users.org/wiki/SplitJoin
Hi I've got this function in JavaScript:
function blur(data) {
var trimdata = trim(data);
var dataSplit = trimdata.split(" ");
var lastWord = dataSplit.pop();
var toBlur = dataSplit.join(" ");
}
What this does is it take's a string such as "Hello my name is bob" and will return
toBlur = "Hello my name is" and lastWord = "bob"
Is there a way i can re-write this in Lua?
You could use Lua's pattern matching facilities:
function blur(data) do
return string.match(data, "^(.*)[ ][^ ]*$")
end
How does the pattern work?
^ # start matching at the beginning of the string
( # open a capturing group ... what is matched inside will be returned
.* # as many arbitrary characters as possible
) # end of capturing group
[ ] # a single literal space (you could omit the square brackets, but I think
# they increase readability
[^ ] # match anything BUT literal spaces... as many as possible
$ # marks the end of the input string
So [ ][^ ]*$ has to match the last word and the preceding space. Therefore, (.*) will return everything in front of it.
For a more direct translation of your JavaScript, first note that there is no split function in Lua. There is table.concat though, which works like join. Since you have to do the splitting manually, you'll probably use a pattern again:
function blur(data) do
local words = {}
for m in string.gmatch("[^ ]+") do
words[#words+1] = m
end
words[#words] = nil -- pops the last word
return table.concat(words, " ")
end
gmatch does not give you a table right away, but an iterator over all matches instead. So you add them to your own temporary table, and call concat on that. words[#words+1] = ... is a Lua idiom to append an element to the end of an array.