Ok so i have a ruby script that currently prompts the user for a string location of a folder on the users harddrive ...this works well
puts "\nEnter the location of the files"
loop do
print "\nLocation: "
reply = ''
reply = STDIN.gets.strip
break if File.directory?(reply)
puts File.directory?(reply)
end
But i was wondering if there was another tool other then the STDIN (which currently makes the user enter a string of the path) that will popup a folder search that the user can navigate to ...if there is anything else I can provide for anyone to help you help me..
I can ever use rails if there is no other option but i have no idea whats available to me
There are a many Ruby GUI libraries; pick one--most will have a file dialog.
For simple dialogs, Zenity is fine.
This is a file selection dialog:
file = `zenity --file-selection --title="Select a file"`.chomp
Adding one parameter changes it to a directory selection dialog:
dir = `zenity --file-selection --directory --title="Select a directory"`.chomp
Related
In a lua-script (for Domoticz # Raspberry) I apply the following script-segment to generate an htm-file and to put it in the designated folder.
Line02text till Line30text are variables which are dynamically filled elsewhere in the lua-script.
file = io.open("/home/pi/domoticz/scripts/lua/XXXXX.htm", "w+")
-- Opens a file named XXXXX.htm (stored under the designated sub-folder of Domoticz)
-- in append mode
-- write lines to opened file
file:write("SOF<br>")
file:write(Line02text .. "<br>")
file:write(Line03text .. "<br>")
....
file:write(Line29text .. "<br>")
file:write(Line30text .. "<br>")
file:write("EOF<br>")
file:close() -- closes the open file
All seems OK, because the htm-file appears as planned.
Next steps would be to copy the file to different folder, open in browser, etc..
But Owner of the htm-file is 'root' and Permission is 0640.
For further application Owner should be different, and Permission e.g. 777.
Trying manual change or use of chmod results in report 'Permission denied' by server.
Question:
How to set (as result of the lua-script) different Owner and other Permission for the htm-file?
Lua's target is to be as portable as possible, and ownership/permissions management is very os-specific. There's no embedded functions to handle that.
You'll need to expose some native function that will do what you need with files' permissions. Or use some already existing library for that, like maybe lua-fs: (https://github.com/clementfarabet/lua-fs-0.3)
I have a Dart [client side only, polymer] web-app. So I cannot use dart.io. I would like to do this semi-pseudo (language/platform mix!) code:
..
String str = "a load of text";
File file = new File('C:\\folder\\test.txt');
file.write(str);
file.close();
or
window.clipboard.copy(str);
so the user can paste it. I have used a TextAreaElement to put the string on (using textarea.value=str), and then the user can copy and paste it himself, but that's a bit naff.
Thanks
Steve
Sorry, you cannot write to files on the file system from a web app. The restriction is from browsers and their security model.
I have a simple modal that appears in which the user is shown the browse button to add the file to upload. Due to an unknown issue, be it the fact its an HTML5 file input therefore the browser adds its own functions to it, this has become a pain to test.
On my page I have:
<input type="file" id="photo_upload">
Capybara offers a solution out of the box which is:
attach_file <<upload_file_id>>, <<file_path>>
This behind the scenes executes a send_keys command to push the file_path into the path container for this input, however this simply did not work with my setup. I am running Firefox 25.0.1 on Windows 8. I tried both a relative path and a full path to this file, with forward and backslash combinations.
When I mean it did not work, I mean when my ajax script executes from clicking the button 'upload' next to it, it does not send any file object in the params.
I even tried to use capybara to send the file path directly:
find_field(<<upload_file_id>>).native.send_keys(<<file_path>>)
Next up, was to attempt to use selenium to push it in using:
element = driver.find_element(:id, <<upload_file_id>>)
element.send_keys <<file_path>>
Then I tried executing script to ensure the element was visible, and then setting it:
element = page.execute_script(
"document.getElementById('#{<<upload_file_id>>}').style.visibility = 'visible';
document.getElementById('#{<<upload_file_id>>}').style.height = '20px';
document.getElementById('#{<<upload_file_id>>}').style.width = '60px';
document.getElementById('#{<<upload_file_id>>}').style.opacity = 1; return
document.getElementById('#{<<upload_file_id>>}')")
find_field(field_locator).native.send_keys(<<file_path>>)
This didn't work either. Now I am completely stuck. All the help on here and google points to using the above, but it just simply does not work for my setup.
My options as far as I can see it are to use a windows automation script and jump out of capybara, run the script, and then continue, or to directly call the upload url either from capybara using a post or calling the js ajax that currently does it.
So I have solved it, and its not too ugly. I used the automation route via AutoIT. The bundle you download with AutoIT includes a script to exe converter and using the below script (I can not take credit for the script) I created an exe:
Local Const $dialogTitle = $CmdLine[2]
Local Const $timeout = 5
Local $windowFound = WinWait($dialogTitle, "", $timeout)
$windowFound = WinWait($dialogTitle, "", $timeout)
Local $windowHandle
If $windowFound Then
$windowHandle = WinGetHandle("[LAST]")
WinActivate($windowHandle)
ControlSetText($windowHandle, "", "[CLASS:Edit; INSTANCE:1]", $CmdLine[1])
ControlClick($windowHandle, "", "[CLASS:Button; TEXT:&Open]")
Else
MsgBox(0, "", "Could not find window.")
Exit 1
EndIf
In my capybara script, I merely run:
find_field(<<upload_file_id>>).click
system("<<full_path>>\\file_upload.exe \"#{<<file_path>>}\" \"File Upload\"")
and it works perfectly! In fact, I think I prefer the fact it exactly mimics what a user would be doing.
I need upload file on the website.
But Have a problem, i can't choose file automatic in code. Always browser show me choose file window.
What wrong in my code?
IE ie = new IE("https://www.xxxx.com/WFrmlogin.aspx");
FileUploadDialogHandler uploadHandler = new FileUploadDialogHandler(#"D:\065-6405_URGENT.xls");
ie.WaitForComplete();
ie.TextField(Find.ById("txtUser")).TypeText("login");
ie.TextField(Find.ById("txtPassWord")).TypeText("***");
ie.Button(Find.ById("btnok")).Click();
ie.WaitForComplete();
ie.GoTo("https://www.orientspareparts.com/inq/WFrmUpOption.aspx");
ie.WaitForComplete();
ie.DialogWatcher.Clear();
ie.AddDialogHandler(uploadHandler);
// This code show choose file dialog
ie.FileUpload(Find.ById("FilUpload")).ClickNoWait();
ie.Button(Find.ById("butUpload")).Click();
ie.WaitForComplete();
I had the same problem. I'm using a GMail-like upload process, so I wanted to test actual use-cases. Just setting the Text property on my hidden file input wasn't an option.
I ended up using SendKeys to type the path to my file, then sent "{ENTER}" to submit the dialog.
SetForegroundWindow(browser.hWnd);
SendKeys.SendWait("{ENTER}");
Thread.Sleep(500); // An unfortunate necessity, to give the dialog time to pop up.
SendKeys.SendWait(#"C:\myfile.jpg{ENTER}")
I don't love this solution, especially not the sleep, but it was the best I could do in under 30 mins.
If anyone has a better option, let me know!
Why do you need to select from the Dialog? Try to just set the Text:
ie.FileUpload(Find.ById("profile_file")).Text = "C:/Desktop/image.jpg";
I guess you might talk to the fellow who asked this question:
WatiN File Upload
My files are referenced like so (it's all relative):
// WHERE YOU KEEP THE PAGE TITLE XML
public static string myPageTitleXML = "xml/pagetitles.xml";
and
using (StreamReader r = new StreamReader(myPageTitleXML))
{ //etc.. . .etc....etc..
}
I get system.io.directorynotfound, and "this problem needs to be shut down", when I double click the executable. But running it from the console works like a charm. What's wrong here?
I played around with attempting to set Environment.CurrentDirectory but couldn't get anything to work. Why should I have to do that anyway? It defeats the purpose of a relative path no?
responding.. .
"application" does not exist in the current context, i'll keep trying what people have mentioned, this is not a windows.form
testing
Path.GetDirectoryName(Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase), myPageTitleXML); gives error URI formats are not supported, as does Path.GetFullPath(). Server.MapPath results in an error as well, this is currently offline
Well assuming this directory is somewhere under the directory in which your code is executing, it sounds like you can use ..
Application.ExecutablePath()
or
Application.StartUpPath()
.. to get an idea as to what your application is seeing when it goes in search of an 'xml' directory with the 'pagetitles.xml' file in it.
If the directory returned by one of these methods does not point where you thought it did, you'll need to move the location of your application or the location of this folder so that it is within the same directory as the app.
Hope this gets you on the right path.
So, when you run it from double clicking the executable, is there a file named pagetitles.xml in a folder named xml, where xml is a folder in the same location as the executable?
It's certainly possible to use relative paths like this, but I wouldn't really recommend it. Instead, maybe use something like:
string fileToOpen = System.IO.Path.Combine(System.IO.Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase), myPageTitleXML);
using (StreamReader r = new StreamReader(fileToOpen))
{
//etc.. . .etc....etc..
}
Is this ASP.NET code? If so then you probably need to do MapPath("xml/pagetitles.xml")