I have non-used elements on my page. In list view I can see them. But now I want to create a page translation for this element. But in the list view there is no "Create new page translation" selection box. How can I create a localized element?
This is what I see? Where is the 2nd option?
In List module click the edit icon (pen symbol) of the content element. At the very top you will see a Language dropdown menu. Any language overlays that do not yet exist are marked with "[NEW]" (see Portuguese in the screenshot below). If you select one of those, the corresponding overlay record is immediately created and a you are presented with a form to fill in its content.
Related
I have a link which says "add another field". On clicking the link a dropdown should appear on top with let's say 5 custom fields as list in dropdown. Once user selects a field in that dropdown and clicks hyperlink another dropdown should appear below existing dropdown and with only 4 remaining fields as one is already selected.so how to start this?
https://tutorialslink.com/Articles/How-to-add-control-dynamically-in-Aspnet-MVC-using-Javascript/64 . I have tried to use this link which adds text boxes to get started.
I don't have any code expect for the code in above link which is for text box though. Just need an idea of how to do it in asp.net MvC as i cannot move forward now.
Expected results is to do the above requirement, don't have any actual results as of now
I've a page called Page where I'll add some blocks called a PageBlock. This two are both document types. Under the Page you could create Pageblocks and Pages. Inside my listview on the backoffice, I'll only show the Pages. In the content three, I'll only show the Pages.
How could I do that?
I've tried to find a filter but nothing found and I wouldn't write a plugin. I'm using Umbraco 7.6
Update: I know how to create an listview but how could I make a filter to show only the childeren of one document type?
I don't know if I understand the question correctly, but I think what you want to do is set the permission of Pages to allow Pageblocks as its children (On the permissions tab of Pages)
Now if you want to display the children of Pages as a listview go to List view (top right) of Pages and enable Yes - Enable list view
If you want to both be able to view children in the tree and in a listview, you can leave the above option unchecked and add a List View property to the Pages documenttype (as displayed in your screenshot)
My page tree looks like this:
Index:
- List
- SingleElement
- Folder
"Folder" contains content elements that i would like to display in a form of a list on page "List". Each element of this list should link to (different) single content element. How can I create such links, and display single content element in page "SingleElement".
2 different content elements are required to solve your questions.
Menu of content elements
To create a menu of content elements, go to your page List and add a content element "Special Menu" (inside the tab "Special elements"). As "Menu Type" please select Section Index and below select the page "List" in the "Selected Pages" field.
Reference of a content element
To reference a content element from one page at another page, use the content element "Insert record" which can be found in the tab "Special Element". At the field "Records" select the content elements you want to reuse.
I've seen in Joomla documentation the way to detect if you are in Frontpage while creating a template in Joomla 2.5. This is the code:
<?php
$app = JFactory::getApplication();
$menu = $app->getMenu();
if ($menu->getActive() == $menu->getDefault()) {
echo 'This is the front page';
}
?>
This works when you are at home page (or clicking on Home menu), but I have an slider in home page, and I link in the slider to an article which is not in any menu item in the application. When I load this article the code above returns as I were at frontpage. I guess that if I doesn't click on any menu item, $menu->getActive() doesn't change.
Any suggestion?
Thanks in advance.
You can do one thing to solve this problem. Create a hidden menu of all the article links which are linked in the sliders.By creating hidden menu the link will be initialized and $menu->getActive() will work for all the links..Hopefully it will works for you .
I wish to add to the present answer and provide some clarifications.
In order for the menu selection to be detected the page requires to be assigned to a menu item. If this is a hidden menu than the link to such a page called My Page would be:
/index.php/my-page - “my-page” is the menu title alias for this item
However, if one wants to show the correct hierarchy in the breadcrumbs for the same page, then the menu hierarchy would have to be replicated in the hidden menu.
For example if My Page is under My Articles main menu item, then in the hidden menu you should add “My Articles” item, of the type: Menu Item Alias, which is in the Systems submenu of the menu type field. The My Page item should be a sub-menu item of My Articles.
The “My Articles” menu item in the hidden menu must have a different menu alias than the same one in the main menu hence the new link to My Page would look like:
/index.php/my-articles2/my-page
To create a hidden menu, one simply creates another menu. It does not matter whether one creates a module for it or not, but if one does then one just should not assign any position to that module.
I have to support a website developed in umbraco. I am totally new to this and this is am working on this for the very first time. My requirement is very straight-I need to edit the content of a webpage. When I too the page it opened with two tabs - Main Content and Properties. In the main content tab I can edit the Title, Banner image, Content header etc, but not the content of the page. It doesn't give any rich textbox to edit the content. I have uploaded the view of one of the page.
I need urgently need to edit the content.Please help with this.
The screenshot implies that the content should be under the "Content" headline in the right screen, but depending on how the documenttype for the frontpage i created, the content could be made up by sub nodes. try folding out the tree to see.
If it dos-nt make sence you can see what documentype a node is made on and what template it uses to display it by clicking the Properties tab. Then go to the Settings Tab in the bottom and see what that documenttype contains and how its displayed in the template