I am using javascript to append user selections to a list. When user is done , which is the best way to go:
1: create index for the list and submit as model in a form to the controller?
2: create hidden element and use javascript to append values and submit as actionlink? (not sure how to tell actionlink the value here)
3: wrap form block around the hidden element only and submit string as model?
other?
I think the easiest way is to put some form of your list to the hidden field (type=hidden) and it will be automatically submitted with form and accessible on server under the name you gave it. So main reasoning here is the way you going to process these data on the server side.
First of all, Scott Hanselman has a good post about model binding to arrays, collections, etc.
In my opinion you shouldn't use second way because this will be a vulnerability ( description of CSRF).
In order to use collections binding you'll need to wrap a form around a list and submit it (note, this form will submit only selected values in this list but you may select them all before submit) or to create a map of values and submit it via javascript (for jQuery - $.post(url, data, callback)) or to add all pairs of name&value to some hidden element of a form and submit it.
Related
In my view, I have a form that'll allow users to build their own car models. I have a field to choose car-parts and another field to add a color for it. For example, a user can choose "tire"=>"yellow". And there's a button to add new entries to the form.
For generating a form in the controller, I have read many articles on not to bind the entity directly to the form, instead use a DTO (data transfer object) to take care of the validation on the $request first. After a success validation may then have the DTO data pass to the entities.
On submit, my form is going to pass field names like "model_name", "part01", "color01", "part02", "color02" to the controller. From the symfony documentation it shows you how to make it works with the use of the "allow_add" option in the form builder. But here's the problem, that was based on the assumption that you're binding your form with the entities, but how about DTO? How do I put all those data into a DTO and tie it to the form and still able to do the validation?
When you want to create a DateTime picker control with JQWidgets, you must define a div element and then call a function like this using Javascript:
$("#MyDivElementId").jqxDateTimeInput().
The problem is: I'm not able to figure out how I can use Model Binding of Asp.Net MVC with this syntax. I mean, the Model Binding feature will try to match key-value pair received from input controls in the form element and obviously, div element are not input control.
I found somebody who already resolved this problem using hidden field set with values of matching div JQWidgets element before submitting form but I don't like this solution; it's not natural and I must write to much code for a thing that should be simpler in my view.
Does anybody have more elegant solution?
If you set the "name" attribute of the DIV tag, the value from the DateTimeInput's Input tag would be submitted.
First of all when you submit id is not submited and i just opened that plugin demo. when you add code $("#MyDivElementId").jqxDateTimeInput(). it will create textarea with name MyDivElementId and when you submit then you will have the same value on server side. Other issue can be with date format since they would be probably different on client side and server side.
try to add input parameter for controller "DateTime MyDivElementId" and check if its null or not.
I have an asp.mvc app the presents to the user different forms when they click on the next button - like a wizard. I do it this way so I can use JQuery to validate each form as the user progresses through them. i.e.
...
// use jquery validator to funk up the form validation
// user clicks the Next button ...
switch(currPageIndex) {
case 0:
if($('#form1'.valid()) {
$('#form1').hide();
$('#form2').show();
}
break;
}
...
However I can't use a single submit button to post the all the forms formcollection data back to my controller - if I do I only get back the one form that the submit button was in and not all of them.
Is there some magic icantation I can type in to get all the forms data sent back to the controller?
Presumably I can cruft up the data myself and send it back to my controller as a jason string, but I'm not sure if this is the best way.
Many thanks.
Wizard-like forms basically rely on a model which is kept on the server-side (in session or a database table) and kept updated.
For example, each post from the client you get back the model from session or database and then call UpdateModel() using the FormCollection which updates the model and the you can check if it is valid.
You can only submit one form at a time, however there are multiple ways around this in your scenario. When you change to the second form you could populate some hidden fields using javascript that would contain the information from the previous form. Then it would all be in the second form and you wouldn't have a problem getting the information.
You could also do it via ajax/json, but then you would probably want to do it with both of the forms data anyway.
In the end I just json'd up the form data and ajax'd it over to the controller, it works very well, nice and and clean to.
many thanks for the replies.
You can do that using $('#form1').submit() function, I don't think there is another way.
Wasnt sure how to word the question, but this is the scenario:
the view is a data entry form eg http://127.0.0.1/User/AddEdit/
so edit the user I have an ID: http://127.0.0.1/User/AddEdit/7838fd9c-425c-4c98-b798-771bba10d9c1
This ID gets the data to populate the form values in a ViewModel, which populates the form
I am using jquery/ajax to save the form, which returns a Json result, indicating ok/error etc
In the View, I get the ID and use this in a hidden field which is set via jquery when the page loads and when the form is saved via ajax.
This seems a bit clunky, how do others do this?
in my opinion best solution is to create a partial view with all the fields and use it on add and edit view which are separate actions in controller. after you create user you can redirect to action edit. if you must / like use ajax you can reload div with form (change from user/add to user/edit/1). i might be wrong but i never see a code or example with one action in controller for add and edit.
I'm new to ASP .NET MVC and to web programming in general.
I'm wondering if there is a way to set ViewData variables when a radiobutton is selected -- but before the page is submitted.
Maybe I'm barking up the wrong tree but what I'm trying to do is create a form where new fields are added based on which radio button is selected. So what I want to do is when a radiobutton is clicked it sets a ViewData variable and based on that ViewData variable a different partial view loads the appropriate fields below the current field.
I imagine there must be someway of doing a onclick="some C# function that sets ViewData(args)"
Thanks
There are a couple of ways you could go about this.
1) You could have an Ajax form where through Javascript you post the form back and check to see if it's an Ajax Request, there by returning a partial view to a div that you specify.
2) Post the form as is and check server-side to see if the radio button was clicked, and thus redisplay the form with the new options visible.
If you take the first approach it would be easy enough to fall through to the second one for those without Javascript enabled.
There aren't really "onclick" events as I'm assuming you are used to from Webforms, you would basically have to roll your own Javascript to handle such things. Once you do a few, I think you'll find it's really not too bad, with the benefit that you'll have more control over what you're doing and through that gain a better understanding of the larger picture.
ViewData only exists, and only exists server-side, for the lifetime of the request. So, once the page is rendered the object no longer exists.
Some alternate approaches you can take:
1 - Use client-side Javascript to add a form and inputs as necessary. More info here:
ASP.NET MVC & JQuery Dynamic Form Content
2 - Pre-render the new form, but hide it via CSS, and unhide it when the appropriate radio button is clicked. More info here:
expand collapse html field Firefox
3 - Use AJAX to render the new form when the appropriate radio button is clicked. More info here:
http://www.asp.net/learn/mvc/tutorial-32-cs.aspx