For a very simple classification problem where I have a target vector [0,0,0,....0] and a prediction vector [0,0.1,0.2,....1] would cross-entropy loss converge better/faster or would MSE loss?
When I plot them it seems to me that MSE loss has a lower error margin. Why would that be?
Or for example when I have the target as [1,1,1,1....1] I get the following:
As complement to the accepted answer, I will answer the following questions
What is the interpretation of MSE loss and cross entropy loss from probability perspective?
Why cross entropy is used for classification and MSE is used for linear regression?
TL;DR Use MSE loss if (random) target variable is from Gaussian distribution and categorical cross entropy loss if (random) target variable is from Multinomial distribution.
MSE (Mean squared error)
One of the assumptions of the linear regression is multi-variant normality. From this it follows that the target variable is normally distributed(more on the assumptions of linear regression can be found here and here).
Gaussian distribution(Normal distribution) with mean and variance is given by
Often in machine learning we deal with distribution with mean 0 and variance 1(Or we transform our data to have mean 0 and variance 1). In this case the normal distribution will be,
This is called standard normal distribution.
For normal distribution model with weight parameter and precision(inverse variance) parameter , the probability of observing a single target t given input x is expressed by the following equation
, where is mean of the distribution and is calculated by model as
Now the probability of target vector given input can be expressed by
Taking natural logarithm of left and right terms yields
Where is log likelihood of normal function. Often training a model involves optimizing the likelihood function with respect to . Now maximum likelihood function for parameter is given by (constant terms with respect to can be omitted),
For training the model omitting the constant doesn't affect the convergence.
This is called squared error and taking the mean yields mean squared error.
,
Cross entropy
Before going into more general cross entropy function, I will explain specific type of cross entropy - binary cross entropy.
Binary Cross entropy
The assumption of binary cross entropy is probability distribution of target variable is drawn from Bernoulli distribution. According to Wikipedia
Bernoulli distribution is the discrete probability distribution of a random variable which
takes the value 1 with probability p and the value 0
with probability q=1-p
Probability of Bernoulli distribution random variable is given by
, where and p is probability of success.
This can be simply written as
Taking negative natural logarithm of both sides yields
, this is called binary cross entropy.
Categorical cross entropy
Generalization of the cross entropy follows the general case
when the random variable is multi-variant(is from Multinomial distribution
) with the following probability distribution
Taking negative natural logarithm of both sides yields categorical cross entropy loss.
,
You sound a little confused...
Comparing the values of MSE & cross-entropy loss and saying that one is lower than the other is like comparing apples to oranges
MSE is for regression problems, while cross-entropy loss is for classification ones; these contexts are mutually exclusive, hence comparing the numerical values of their corresponding loss measures makes no sense
When your prediction vector is like [0,0.1,0.2,....1] (i.e. with non-integer components), as you say, the problem is a regression (and not a classification) one; in classification settings, we usually use one-hot encoded target vectors, where only one component is 1 and the rest are 0
A target vector of [1,1,1,1....1] could be the case either in a regression setting, or in a multi-label multi-class classification, i.e. where the output may belong to more than one class simultaneously
On top of these, your plot choice, with the percentage (?) of predictions in the horizontal axis, is puzzling - I have never seen such plots in ML diagnostics, and I am not quite sure what exactly they represent or why they can be useful...
If you like a detailed discussion of the cross-entropy loss & accuracy in classification settings, you may have a look at this answer of mine.
I tend to disagree with the previously given answers. The point is that the cross-entropy and MSE loss are the same.
The modern NN learn their parameters using maximum likelihood estimation (MLE) of the parameter space. The maximum likelihood estimator is given by argmax of the product of probability distribution over the parameter space. If we apply a log transformation and scale the MLE by the number of free parameters, we will get an expectation of the empirical distribution defined by the training data.
Furthermore, we can assume different priors, e.g. Gaussian or Bernoulli, which yield either the MSE loss or negative log-likelihood of the sigmoid function.
For further reading:
Ian Goodfellow "Deep Learning"
A simple answer to your first question:
For a very simple classification problem ... would cross-entropy loss converge better/faster or would MSE loss?
is that MSE loss, when combined with sigmoid activation, will result in non-convex cost function with multiple local minima. This is explained by Prof Andrew Ng in his lecture:
Lecture 6.4 — Logistic Regression | Cost Function — [ Machine Learning | Andrew Ng]
I imagine the same applies to multiclass classification with softmax activation.
In cs231n handout here, it says
New dataset is small and similar to original dataset. Since the data
is small, it is not a good idea to fine-tune the ConvNet due to
overfitting concerns... Hence, the best idea might be to train a
linear classifier on the CNN codes.
I'm not sure what linear classifier means. Does the linear classifier refer to the last fully connected layer? (For example, in Alexnet, there are three fully connected layers. Does the linear classifier the last fully connected layer?)
Usually when people say "linear classifier" they refer to Linear SVM (support vector machine). A linear classifier learns a weight vecotr w and a threshold (aka "bias") b such that for each example x the sign of
<w, x> + b
is positive for the "positive" class and negative for the "negative" class.
The last (usually fully connected) layer of a neural-net can be considered as a form of a linear classifier.
I am new to machine learning and I am currently working on classification problem. I am able to train the model and predict test data sets. I want to know whether is there some way by which I can get scores along with the prediction. By scores , I mean those are proximity scores along with prediction. For example, in standard age-salary-buy (based on age and salary whether the customer will buy the product or not) classification problem, I want to know what is a score out of 100 that he will buy that product in addition to the prediction of whether he will buy it or not.
Currently, I am using LibSVM Algo. Is there some algo which provides me above data ?
Thanks.
What you are looking for is a support of your decision. In other words, many classifiers base their decision of x class over labels Y on:
cl(x) = arg max_{y \in Y} p(y|x)
where p(y|x) is their internal estimation of "x having label y". And such classifiers include:
neural networks (with sigmoid output)
logistic regression
naive bayes
voting ensembles (such as RF)
...
These methods can be easily converted to your 0-100 scale, as probability is in 0-1 scale.
Some, on the other hand use measure proportional to probability (such as SVM), but unbounded, here you can get this value (often called decision function) but you cannot convert it to 0-100 score (as you do not have "maximum" value). This is a big drawback, so some modification were proposed. In particular for SVM you have Platt's scaling which actually fits a logistic regression on top of SVM so you get your probability estimate. In libSVM you can set -b to get probability estimates
from libsvm website
-b probability_estimates: whether to train a SVC or SVR model for probability estimates, 0 or 1 (default 0)
Suppose I have a dataset which only has one continuous variable, and I try to use decision tree algorithm to build a model which classify the +ve and -ve label from the dataset. I run 10-fold cross-validation.
How does the AUC being calculated for the Decision Tree classifier? Will the algorithm check different threshold value of the classifier, and determine the AUC?
What about I have more than 2 continuous variable?
Thanks!
Off topic, but hey:
AUC only makes sense for binary classification. The number of predictors does not matter.
Decision trees do not inherently have a 'threshold' but typically in a classification problem, the leaves contain a probability distribution over the 2 classes, and so does the tree's prediction. So you could conceive of picking the positive class only if its probability is >= p, not just >= 0.5. Then you could draw an AUC curve.
So it's a little unnatural to apply this to a decision tree but can be done.
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When we have to predict the value of a categorical (or discrete) outcome we use logistic regression. I believe we use linear regression to also predict the value of an outcome given the input values.
Then, what is the difference between the two methodologies?
Linear regression output as probabilities
It's tempting to use the linear regression output as probabilities but it's a mistake because the output can be negative, and greater than 1 whereas probability can not. As regression might actually
produce probabilities that could be less than 0, or even bigger than
1, logistic regression was introduced.
Source: http://gerardnico.com/wiki/data_mining/simple_logistic_regression
Outcome
In linear regression, the outcome (dependent variable) is continuous.
It can have any one of an infinite number of possible values.
In logistic regression, the outcome (dependent variable) has only a limited number of possible values.
The dependent variable
Logistic regression is used when the response variable is categorical in nature. For instance, yes/no, true/false, red/green/blue,
1st/2nd/3rd/4th, etc.
Linear regression is used when your response variable is continuous. For instance, weight, height, number of hours, etc.
Equation
Linear regression gives an equation which is of the form Y = mX + C,
means equation with degree 1.
However, logistic regression gives an equation which is of the form
Y = eX + e-X
Coefficient interpretation
In linear regression, the coefficient interpretation of independent variables are quite straightforward (i.e. holding all other variables constant, with a unit increase in this variable, the dependent variable is expected to increase/decrease by xxx).
However, in logistic regression, depends on the family (binomial, Poisson,
etc.) and link (log, logit, inverse-log, etc.) you use, the interpretation is different.
Error minimization technique
Linear regression uses ordinary least squares method to minimise the
errors and arrive at a best possible fit, while logistic regression
uses maximum likelihood method to arrive at the solution.
Linear regression is usually solved by minimizing the least squares error of the model to the data, therefore large errors are penalized quadratically.
Logistic regression is just the opposite. Using the logistic loss function causes large errors to be penalized to an asymptotically constant.
Consider linear regression on categorical {0, 1} outcomes to see why this is a problem. If your model predicts the outcome is 38, when the truth is 1, you've lost nothing. Linear regression would try to reduce that 38, logistic wouldn't (as much)2.
In linear regression, the outcome (dependent variable) is continuous. It can have any one of an infinite number of possible values. In logistic regression, the outcome (dependent variable) has only a limited number of possible values.
For instance, if X contains the area in square feet of houses, and Y contains the corresponding sale price of those houses, you could use linear regression to predict selling price as a function of house size. While the possible selling price may not actually be any, there are so many possible values that a linear regression model would be chosen.
If, instead, you wanted to predict, based on size, whether a house would sell for more than $200K, you would use logistic regression. The possible outputs are either Yes, the house will sell for more than $200K, or No, the house will not.
Just to add on the previous answers.
Linear regression
Is meant to resolve the problem of predicting/estimating the output value for a given element X (say f(x)). The result of the prediction is a continuous function where the values may be positive or negative. In this case you normally have an input dataset with lots of examples and the output value for each one of them. The goal is to be able to fit a model to this data set so you are able to predict that output for new different/never seen elements. Following is the classical example of fitting a line to set of points, but in general linear regression could be used to fit more complex models (using higher polynomial degrees):
Resolving the problem
Linear regression can be solved in two different ways:
Normal equation (direct way to solve the problem)
Gradient descent (Iterative approach)
Logistic regression
Is meant to resolve classification problems where given an element you have to classify the same in N categories. Typical examples are, for example, given a mail to classify it as spam or not, or given a vehicle find to which category it belongs (car, truck, van, etc ..). That's basically the output is a finite set of discrete values.
Resolving the problem
Logistic regression problems could be resolved only by using Gradient descent. The formulation in general is very similar to linear regression the only difference is the usage of different hypothesis function. In linear regression the hypothesis has the form:
h(x) = theta_0 + theta_1*x_1 + theta_2*x_2 ..
where theta is the model we are trying to fit and [1, x_1, x_2, ..] is the input vector. In logistic regression the hypothesis function is different:
g(x) = 1 / (1 + e^-x)
This function has a nice property, basically it maps any value to the range [0,1] which is appropiate to handle propababilities during the classificatin. For example in case of a binary classification g(X) could be interpreted as the probability to belong to the positive class. In this case normally you have different classes that are separated with a decision boundary which basically a curve that decides the separation between the different classes. Following is an example of dataset separated in two classes.
You can also use the below code to generate the linear regression
curve
q_df = details_df
# q_df = pd.get_dummies(q_df)
q_df = pd.get_dummies(q_df, columns=[
"1",
"2",
"3",
"4",
"5",
"6",
"7",
"8",
"9"
])
q_1_df = q_df["1"]
q_df = q_df.drop(["2", "3", "4", "5"], axis=1)
(import statsmodels.api as sm)
x = sm.add_constant(q_df)
train_x, test_x, train_y, test_y = sklearn.model_selection.train_test_split(
x, q3_rechange_delay_df, test_size=0.2, random_state=123 )
lmod = sm.OLS(train_y, train_x).fit() lmod.summary()
lmod.predict()[:10]
lmod.get_prediction().summary_frame()[:10]
sm.qqplot(lmod.resid,line="q") plt.title("Q-Q plot of Standardized
Residuals") plt.show()
Simply put, linear regression is a regression algorithm, which outpus a possible continous and infinite value; logistic regression is considered as a binary classifier algorithm, which outputs the 'probability' of the input belonging to a label (0 or 1).
The basic difference :
Linear regression is basically a regression model which means its will give a non discreet/continuous output of a function. So this approach gives the value. For example : given x what is f(x)
For example given a training set of different factors and the price of a property after training we can provide the required factors to determine what will be the property price.
Logistic regression is basically a binary classification algorithm which means that here there will be discreet valued output for the function . For example : for a given x if f(x)>threshold classify it to be 1 else classify it to be 0.
For example given a set of brain tumour size as training data we can use the size as input to determine whether its a benine or malignant tumour. Therefore here the output is discreet either 0 or 1.
*here the function is basically the hypothesis function
They are both quite similar in solving for the solution, but as others have said, one (Logistic Regression) is for predicting a category "fit" (Y/N or 1/0), and the other (Linear Regression) is for predicting a value.
So if you want to predict if you have cancer Y/N (or a probability) - use logistic. If you want to know how many years you will live to - use Linear Regression !
Regression means continuous variable, Linear means there is linear relation between y and x.
Ex= You are trying to predict salary from no of years of experience. So here salary is independent variable(y) and yrs of experience is dependent variable(x).
y=b0+ b1*x1
We are trying to find optimum value of constant b0 and b1 which will give us best fitting line for your observation data.
It is a equation of line which gives continuous value from x=0 to very large value.
This line is called Linear regression model.
Logistic regression is type of classification technique. Dnt be misled by term regression. Here we predict whether y=0 or 1.
Here we first need to find p(y=1) (wprobability of y=1) given x from formuale below.
Probaibility p is related to y by below formuale
Ex=we can make classification of tumour having more than 50% chance of having cancer as 1 and tumour having less than 50% chance of having cancer as 0.
Here red point will be predicted as 0 whereas green point will be predicted as 1.
Cannot agree more with the above comments.
Above that, there are some more differences like
In Linear Regression, residuals are assumed to be normally distributed.
In Logistic Regression, residuals need to be independent but not normally distributed.
Linear Regression assumes that a constant change in the value of the explanatory variable results in constant change in the response variable.
This assumption does not hold if the value of the response variable represents a probability (in Logistic Regression)
GLM(Generalized linear models) does not assume a linear relationship between dependent and independent variables. However, it assumes a linear relationship between link function and independent variables in logit model.
| Basis | Linear | Logistic |
|-----------------------------------------------------------------|--------------------------------------------------------------------------------|---------------------------------------------------------------------------------------------------------------------|
| Basic | The data is modelled using a straight line. | The probability of some obtained event is represented as a linear function of a combination of predictor variables. |
| Linear relationship between dependent and independent variables | Is required | Not required |
| The independent variable | Could be correlated with each other. (Specially in multiple linear regression) | Should not be correlated with each other (no multicollinearity exist). |
In short:
Linear Regression gives continuous output. i.e. any value between a range of values.
Logistic Regression gives discrete output. i.e. Yes/No, 0/1 kind of outputs.
To put it simply, if in linear regression model more test cases arrive which are far away from the threshold(say =0.5)for a prediction of y=1 and y=0. Then in that case the hypothesis will change and become worse.Therefore linear regression model is not used for classification problem.
Another Problem is that if the classification is y=0 and y=1, h(x) can be > 1 or < 0.So we use Logistic regression were 0<=h(x)<=1.
Logistic Regression is used in predicting categorical outputs like Yes/No, Low/Medium/High etc. You have basically 2 types of logistic regression Binary Logistic Regression (Yes/No, Approved/Disapproved) or Multi-class Logistic regression (Low/Medium/High, digits from 0-9 etc)
On the other hand, linear regression is if your dependent variable (y) is continuous.
y = mx + c is a simple linear regression equation (m = slope and c is the y-intercept). Multilinear regression has more than 1 independent variable (x1,x2,x3 ... etc)
In linear regression the outcome is continuous whereas in logistic regression, the outcome has only a limited number of possible values(discrete).
example:
In a scenario,the given value of x is size of a plot in square feet then predicting y ie rate of the plot comes under linear regression.
If, instead, you wanted to predict, based on size, whether the plot would sell for more than 300000 Rs, you would use logistic regression. The possible outputs are either Yes, the plot will sell for more than 300000 Rs, or No.
In case of Linear Regression the outcome is continuous while in case of Logistic Regression outcome is discrete (not continuous)
To perform Linear regression we require a linear relationship between the dependent and independent variables. But to perform Logistic regression we do not require a linear relationship between the dependent and independent variables.
Linear Regression is all about fitting a straight line in the data while Logistic Regression is about fitting a curve to the data.
Linear Regression is a regression algorithm for Machine Learning while Logistic Regression is a classification Algorithm for machine learning.
Linear regression assumes gaussian (or normal) distribution of dependent variable. Logistic regression assumes binomial distribution of dependent variable.
The basic difference between Linear Regression and Logistic Regression is :
Linear Regression is used to predict a continuous or numerical value but when we are looking for predicting a value that is categorical Logistic Regression come into picture.
Logistic Regression is used for binary classification.