I'm creating an animated (in and out) drop down menu.
I've managed to get the menu to open when the user mouses over, with the buttons all selectable.
However I can't seem to find an efficient method of making the drop down menu close whenever the mouse is not over the menu.
Actions:
Nav_Main_Sports.addEventListener(MouseEvent.MOUSE_OVER, Nav_Main_Sports_Open);
Nav_Main_Sports_Out.addEventListener(Event.MOUSE_LEAVE, Nav_Main_Sports_Close);
function Nav_Main_Sports_Open(event:MouseEvent):void
{
gotoAndPlay(2);
}
function Nav_Main_Sports_Close(event:MouseEvent):void
{
gotoAndPlay(14);
}
Stops are included, but on a separate layer.
All help would be appreciated. Thanks in advanced.
Actions:
Nav_Main_Sports.addEventListener(MouseEvent.ROLL_OVER, Nav_Main_Sports_Open);
Nav_Main_Sports.addEventListener(MouseEvent.ROLL_OUT, Nav_Main_Sports_Close);
function Nav_Main_Sports_Open(event:MouseEvent):void
{
Nav_Main_Sports.gotoAndPlay(2);
}
function Nav_Main_Sports_Close(event:MouseEvent):void
{
Nav_Main_Sports.gotoAndPlay(14);
}
Worked out the best method for this, use ROLL_OVER and ROLL_OUT and refer to the drop down menu in the function. This worked perfectly for me.
Try this:
Nav_Main_Sports.addEventListener(MouseEvent.MOUSE_OUT, Nav_Main_Sports_Close);
EDIT:
If you want to get the event on the whole swf, do stage.addEventListener(MouseEvent.MOUSE_OUT, Nav_Main_Sports_Close);
Related
JQUERY CODE:
$('#selector button').click(function() {
$(this).addClass('active').siblings().removeClass('active');
$('#gaga').toggle
})
PUG CODE FOR #gaga element:
p#gaga
| This is `${Value}`
PUG CODE FOR #gaga element:
How can I use three buttons to toggle the #gaga element on when button is active and off when you click outside the specific button and pass a different Value for ${Value} depending on the clicked button. Plus have only one instance of #gaga element running at a time. Meaning if I click the first button then click the second button only the ${Value} will change but the p#gaga element remains only one. I know I have left out the buttons pug code, I don't think it is necessary in solving the problem. But if needed will provide it.
I tried doing it using switch statements but I have failed. Hopefully someone can help.
UPDATE & EDIT as requested by https://stackoverflow.com/users/463319/twisty in the comments.
Here is the code: https://jsfiddle.net/YulePale/mdvnf0qt/4/
After doing some research I have made some progress... but I am still stuck.
I am trying to make it in such a way that when I click anywhere outside the gender buttons the input disappears and when I click another button it changes appropriately. Also instead of an input I want to show and hide the template in the html code.
Also, if you don't mind is .data() use to assign or get a value.
PS: Got this code from this answer : Fixing toggle with two buttons
and modified it a bit, but I am still not able to achieve my desired result.
If you review the API for Menu, they have a nice _closeOnDocumentClick(). You can simply use this in your code in a similar way.
Example: https://jsfiddle.net/Twisty/0x43bf8q/
JavaScript
$(function() {
$("input[type='button']").on('click', toggleOptions)
.first()
.trigger('click');
$(document).on("click", function(e) {
if (emptyOnDocumentClick(e)) {
$('[name=gender]').val("");
}
});
function toggleOptions() {
var $this = $(this),
onClass = 'button-toggle-on';
$this.toggleClass(onClass)
.siblings('input[type=button]')
.removeClass(onClass);
var gender = $this.filter('.' + onClass).data('gender');
$('[name=gender]').val(gender);
}
function emptyOnDocumentClick(event) {
return !$(event.target).closest("input[type='button']").length;
}
});
Hope that helps.
I'm trying to fire an event programmatically. My problem is that I have two SVG on two DIVs and I want to be able to change the border of the DIV I have clicked. To do that I thought to pass the DIV inside my classes and then trigger a click on it once I click on anything. (if there is a better way, please tell me)
I have the following code:
div = querySelector(divName);
svgElement = new svg.SvgSvgElement();
div.append(svgElement);
div.onClick.listen(_setBorders(1));
later I pass the svgElement to another class
ell.show(svgElement);
where show is
show(svg.SvgElement element) {
if (element.parent is DivElement){
_parentDiv= element.parent as DivElement;
element.children.add(_group);
}
}
_parentDiv is of course a DivElement, which I use for an internal onClick()
_onClick(MouseEvent e) {
window.console.info("onClick Ell");
_parentDiv.click();
}
I'm expecting to see the _setBorders(1); I defined with the main div, but it doesn't work. The weird thing is that when I check with the debugger set to the _parentDiv.click() I see that _parentDiv has the event correctly set.
I suppose click() doesn't work as I expected. Any Idea?
If you want that _setBorders(1) is called on click events you have to use :
div.onClick.listen((_) => _setBorders(1));
I am trying to use the ShowHide effect that comes with Kevin Moore's widget package here:
http://dart-lang.github.io/widget.dart/#showhide
Not sure how to use this. Anyone got an example I can look at ?
Basically all I want is for a dropdown to show with one of those effects if a certain event happens.
Your tips appreciated.
Thanks.
You need to add a listener for an event to an element in the DOM, and then use ShowHide.toggle(element, effect) to trigger an effect. Here is an example which listens for a click on a button, and toggles FadeEffect on an image each time it is pressed:
var button = query("#fadeButton")
..onClick.listen((event) {
ShowHide.toggle(query("#fadeImage"), effect: new FadeEffect());
});
If you wanted to fade in/out a dropdown when you click on a menu bar, then substitute "fadeButton" for the menu which listens for clicks, and "fadeImage" with the dropdown element.
Also, any other effect can be substituted for FadeEffect, such as DoorEffect, ScaleEffect, ShrinkEffect, etc.
I've implemented drag and drop OK with jQueryUI draggable and droppable.
For the less savvy users, I'd like to also offer a visible "move" button. When they click this button, the element would be picked up, and when they click again on a drop target, it's dropped. So the same as drag and drop, but started with one click and dropped with another.
I know it would be possible to do this with separate code, but I'd rather not reinvent everything for a slight variation. Is there a way to get jQueryUI to do this?
The only thing I found is calling the trigger method of the draggable, but you have to pass a mousedown event...
Thanks
See my answer on this other question. If you change it so instead of
$("#headerDiv")
.mousedown(function(event) {
x = event.pageX;
y = event.pageY;
$(this).parent().addClass('movable');
})
.mouseup(function() {
$(this).parent().removeClass('movable');
});
bind to click and implement a toggling mechanism to decide if you are beginning the drag (mousedown equivalent) or ending the drag (mouseup equivalent) you should be most of the way there.
I would use .animate to animate the object to its target. I have done this before with a game. For example you could specify top and left coordinates for the element to move to onClick of the button.
I am having a bit of a problem with an app I'm developing for BlackBerry.
I have a series of Item objects on the screen, each with a DefaultCommand tied to it. Example
below:
...
cmdBrowse = new Command(temp.id,Command.ITEM,0);
mainList.setDefaultCommand(cmdBrowse);
mainList.setItemCommandListener(icl);
...
Previously just clicking on the item with the confirm button would run the proper command. No problem there.
Then I added the handleKeyReleased method to capture the BlackBerry's back button as follows:
protected boolean handleKeyReleased(int keyCode, int gameAction) {
if(keyCode==1769472) {
/*code to deal with back button*/
return true;
} else {
return false;
}
}
Now when I click on the mainList Item with the confirm button, it brings up the list of commands first and I have to click again to actually run the command. Two clicks where it used to be one.
So, is there a way to either:
A. Keep the single click behaviour while still being able to capture the back button with handleKeyReleased
or
B. Capture the back button in a different way ?
I ended up overlooking one very simple thing. All I had to do was call the superclass's handleKeyReleased method and everything worked perfectly.